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Hey wat was to b done in vector last part? 32
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The 94% probability is the area in the MIDDLE, which means there is a "tail" on either side, of 3% probability. When you look for z value you need to count from the left side, or negative infinity. So here the probability is 0.94 + 0.03 = 0.97in ON11 P61, Q 5i, Why have they taken the probability as .97 instead of .94 ?
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_61.pdf
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_ms_61.pdf
whenever they use the word USING SUITABLE APPROXIMATION in the questionplease how I know I have to use the continuity correction in the normal distribution problems??
ok but there is a problem in nov 11 variant 2 or 3 i think they say random sample and in the mark scheme they used the continuity correction !!whenever they use the word USING SUITABLE APPROXIMATION in the question
i cant check it right now busy with my chem exam tomorrow when i am free i will try and figure it out and explainok but there is a problem in nov 11 variant 2 or 3 i think they say random sample and in the mark scheme they used the continuity correction !!
Between 5000 and 6000, so the first digit must be 5.can somone please explain question 5 :a (ii)
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w09_qp_61.pdf
[number without pink next to green] = [total number] - [number with pink next to green]in MJ10 p6 variant 2, Q 7 the last part (v)---- don't get it.
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_62.pdf
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_ms_62.pdf
thanks[number without pink next to green] = [total number] - [number with pink next to green]
total number, as calculated in (iii), is 9P3 = 504
number with pink next to green can be done this way:
- find the number of choices that has both the pink and green cards, which is just, with the pink and green removed, choosing 1 extra from 7.
1 × 1 × 7C1 = 7
- find the number of arrangements of the three chosen cards that have the pink next to green.
2! × 2! = 4
So overall with pink next to green there are 7 × 4 = 28 arrangements
504 - 28 = 476 arrangements without pink next to green.
ok thats fine, and good luck for tomorrow exami cant check it right now busy with my chem exam tomorrow when i am free i will try and figure it out and explain
Continuity correction is used when we approximate a discrete variable using a continuous variable. Like using X~N to approximate X~B, or X~N approximate X~Poplease any help when we use the continuity correction in solving the normal distribution problems, for example in june 11 paper 62 there is a question using normal approximation and in the mark scheme they used the continuity correction !!!!
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