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Physics: Post your doubts here!

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1357913579

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goodluckayesha said:
0.7 is the slit separation n the 2 small holes r the slits
so whts the doubt??
Click to expand...
my labeling is correct for showing which one is the width?
becuase if the its correct then if u increase the slit seperation than the distance between the slits( slit width) decreases isnt it? so
 
goodluckayesha

goodluckayesha

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1357913579 said:
my labeling is correct for showing which one is the width?
becuase if the its correct then if u increase the slit seperation than the distance between the slits( slit width) decreases isnt it? so
Click to expand...
yh label is correct n no width of slit n slit separation have no connection
but ur using rong words distance between the slits is slit separation
 
Dug

Dug

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cyclone94 said:
gary221 or Dug........any1 plzzz help wid dis asap...
m/j-11-43 qs 12
Click to expand...
a)
i) Signal-to-noise ratio = 10lg(Signal power/Noise power)
Let minimum signal power = P
24 = 10lg(P/(5.6x10^-19)
P = 1.4x10^-16 W

ii) Attenuation per length = (1/L) 10lg(P-in/P-out)
1.9 = 1/L 10lg(3.5x10^-3/1.4x10^-6)
L = 71 km
 
Warrior66

Warrior66

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mrnt3250 said:
This type of question has always been a disaster for me :p
Can you write all the possible effects of changes to the apparatus? (The ones you said, and also other changes like moving the screen further, changing wavelength, changing slit separation, etc.)
Click to expand...
Well for the most basic relationships..you can use the formula pi = ax/D.
like for example, increasing the distance 'D' between the screen & the double slits whilst keeping everything same..the fringe separation 'x' increases.
 
gary221

gary221

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Sapphires said:
Please help me with these questions - 6c (ii) Please draw the graph. and question 5b (ii)
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w05_qp_4.pdf gary221 or Dug please. Thank you!
Click to expand...

5 b ii) 1 In the equation, 1/2mv^2 = qV
mass n charge are constant, so velocity is directly proportional to p.d.
Reducing the pd ---> velocity of the particle will also decrease.
So, the deflection will b larger.

2 the magnetic field is providing the centripetal force in this case. So, when mag. field strength increases, the force exerted by it also increases ( F = BIl)
So, since the centripetal force now increases, the deflection will again b larger!

Hope u gt it!
 
Sapphires

Sapphires

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gary221 said:
5 b ii) 1 In the equation, 1/2mv^2 = qV
mass n charge are constant, so velocity is directly proportional to p.d.
Reducing the pd ---> velocity of the particle will also decrease.
So, the deflection will b larger.

2 the magnetic field is providing the centripetal force in this case. So, when mag. field strength increases, the force exerted by it also increases ( F = BIl)
So, since the centripetal force now increases, the deflection will again b larger!

Hope u gt it!
Click to expand...
Thank you so much. :) Yes, I get it.
I needed help with 6c ii graph as well, please?
 
SalmanslK

SalmanslK

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question.png


HELP !!
 
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