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Asalam-o-Alaikum! (reposting this question again)
is it true that the brightness of the fringes increases by increasing the width of both the slits without changing the separation 'a' between the slits? I thought that narrowing the slits makes the fringes brighter?
If its not too much trouble, could you please tell me all the relationships concerning the diffraction grating that the examiners frequently ask us about?
gary221?
Thanks a bunch!!
think abt it this way. As u increase the width u let in more light thus at the point previously where u had constructive interference, over there now more waves will coincide due to the widening of the gaps. Thus the brightness increase.
Thank you!Determining wavelength using a grating ---> d sinΘ = n
whr d = distance btw adjacent lines on the grating.
n = order of the maximum. only has 2 integer values (0, 1, 2, 3)
normally, they dont give u d outright...
bt sth like " the grating has 3000 lines per cm" ---> n u have 2 calculate d from this
ie d = 1 cm/no. of lines
d = 1/3000 = 3.33 * 10^-6 m
gary221, I did come across the answer you posted above but I didn't quite get it...could you please answer it for me?
Jazaka'Allahum Khairan!M not giving AS this yr..bt let me try..
when u increase the width of the slits ---> more light now enters thru them.
So, both the interferences will increase as now more light = move waves = more constructive as well as destructive interfernces will take place.
ie more waves will coincide ---> leading to brighter fringes(as well as darker fringes).
Decreasing width increases sharpness of the fringes...nt brightness.
as light is not spread out..fringes will be sharper, but since lesser waves now coincide --> fringes will b less bright!!
Hope u gt it!!
This type of question has always been a disaster for meJazaka'Allahum Khairan!
u need 2 find out k for wave A in terms of I. (I=ka2) then substitute this value of k in I'=ka2_formula for wave B. amplitude is read from the waveforms displaced. the new intensity of wave B is I'http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w05_qp_2.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w05_ms_2.pdf
umm... plz explain question 5 part ci n cii as im unable to understand them from the mark scheme part cii can be done by ratio method too but I cant work it out so plz help with it
thnqu need 2 find out k for wave A in terms of I. (I=ka2) then substitute this value of k in I'=ka2_formula for wave B. amplitude is read from the waveforms displaced. the new intensity of wave B is I'
did u understand??Thank youuuu so much!
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w07_qp_2.pdfJazaka'Allahum Khairan!
the separation of slits is increased not the width of each slit so brightness wud remain samehttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w07_qp_2.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w07_ms_2.pdf
in this question 5c(ii) in ms its written theres no effect on brightness how?
because i totally agree with gary's statement
the separation of slits is increased not the width of each slit so brightness wud remain same
my labeling is correct for showing which one is the width?0.7 is the slit separation n the 2 small holes r the slits
so whts the doubt??
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