Physics: Post your doubts here!

[Areeba Khan]

answer is 3.2 .....i got it actually ...anyways thanks

 

[Manobilly]

I have a tiny doubt any1 awake to answer?,

 

[axetreme.O]

answer is 3.2 .....i got it actually ...anyways thanks

how?

 

[Areeba Khan]

uve rea

how?

uve read da question ryt?

 

[axetreme.O]

uve rea

uve read da question ryt?

ofcourse.

 

[axetreme.O]

I have a tiny doubt any1 awake to answer?,

you could post the doubt instead of this.....

 

[Obsidian Fl1ght]

In Kinematic graphs, is (KE, t) equal to (v, t)?

 

[Manobilly]

Tr

you could post the doubt instead of this.....

tried it 2 times in here,no one bothers answering -_-

 

[Areeba Khan]

so frst well calculate I3 i.e : 12/6 = 2 A
dn I2 i.e = 12/10 ( resistance of wire given in ques) =1.2A
nd as I1 = I2+I3 so it wud b = 1.2 + 2 = 3.2 A

 

[lee mee..]

answer is 3.2 .....i got it actually ...anyways thanks

Do u know how to do part b of this question ?

 

[Areeba Khan]

Do u know how to do part b of this question ?

um y dun u take a look at the marking scheme im sure ull gt it here :

p.d. BC: 12 – 12 × 0.4 = 7.2 (V) / p.d. AC = 4.8(V) C1
p.d. BD: 12 – 12 × 4 / 6 = 4.0 (V) / p.d. AD = 8.0(V) C1
p.d. = 3.2V

 

[Areeba Khan]

voltage in parallel is equal..? may be yes..if the answer is the same as you got in mark scheme.

dey r in series :? 4 n 2 ohm resistor

 

[axetreme.O]

dey r in series :? 4 n 2 ohm resistor

i am talking about voltage not resistance..

 

[Areeba Khan]

i am talking about voltage not resistance..

yes dey r parallel so voltage wud b da same

 

[Ariel Robert]

so frst well calculate I3 i.e : 12/6 = 2 A
dn I2 i.e = 12/10 ( resistance of wire given in ques) =1.2A
nd as I1 = I2+I3 so it wud b = 1.2 + 2 = 3.2 A

Or You could simply take 3 resistors in parallel and then 12/resistors in parallel...

 

[axetreme.O]

yes dey r parallel so voltage wud b da same

cleared.

 

[lee mee..]

um y dun u take a look at the marking scheme im sure ull gt it here :

p.d. BC: 12 – 12 × 0.4 = 7.2 (V) / p.d. AC = 4.8(V) C1
p.d. BD: 12 – 12 × 4 / 6 = 4.0 (V) / p.d. AD = 8.0(V) C1
p.d. = 3.2V

weeelll ... actually i didn't get it ..

 

[sma786]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s12_qp_21.pdf
Question 5, b(ii), why for R they divided 0.9 by 1 ? then why *4?

 

[ZainH]

Is this correct?
Blue line is where maxima would be observed and red line is where minima would be observed.

 

[daredevil]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s12_qp_21.pdf
Question 5, b(ii), why for R they divided 0.9 by 1 ? then why *4?

because 1m is the total length and the part of the length they are taking is 0.9 as u know R is directly proportional to length.
and then the resistance of the total length is 4 ohm they multiply by 4.
if u don't get it this way then use the ratio method: -

0.9 : x
1 : 4

cross multiply and u willl get (0.9/1) * 4