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Is the zeroth order considered a maxima?
And can you please explain no 24 from s10 p11?
And can you please explain no 24 from s10 p11?
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Thanks a lotmomentum is M1V1-M2V2
that is 60m-40m=20m
elastic collision occurs as it is frictionless. M doubled as they stick to eachother so speed halves. 20/2=10
OR just use any value for mass and calculate. For example, mass=10kg. Then before collision momentum= (60*10)-(40*10)=200
after collision should also be 200kgms-1 so mass*velocity=200
as the 2 masses stick the mass is now 10+10 = 20kg
so velocity = 200/20=10
hey there raweeha its marwaGot it finally!
May Allah reward you for persevering with my thick-headed-ness (sorry physics is not my thing)
Thank you
hey there raweeha its marwa
An easy way is to use the units method we learnt in the 1st chap in D the units cancel eachother out but in A they wont its just a tiphttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s10_qp_11.pdf
I need some help with qn no 16.. why is the answer D and not A?
Thanks
its A. wavelength should be larger than the gap for diffraction. In a frequency in increasing so wavelength will decrease. hence less diffractionIs the zeroth order considered a maxima?
And can you please explain no 24 from s10 p11?
the qstns i anwered in the other post. For the image last question - 1st find the current. total R=7.5 then 2/7.5=0.26A. as it is parallel circuit current gets divided so 0.26/2=0.13 or 2/15 for easier calculation. then find V across X. V=IR = (2/15)*5 = 2/3Vquoted from other thread .... >>>help
1__Two springs P and Q both obey Hooke’s law. They have spring constants 2k and k respectively.
The springs are stretched, separately, by a force that is gradually increased from zero up to a
certain maximum value, the same for each spring. The work done in stretching spring P is WP,
and the work done in stretching spring Q is WQ.
How is WP related to WQ?
A WP =
1/4 WQ B WP =1/2 [1] WQ C WP = 2WQ D WP = 4WQ
i get C ... but the answer is B
2___A wave of amplitude a has an intensity of 3.0Wm–2.
What is the intensity of a wave of the same frequency that has an amplitude 2a
A_12 .. i used I>A^2 and still not coming
Q22- E=F*l/A*extensionhttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w09_qp_11.pdf
help! question 22 and 26 please!
An easy way is to use the units method we learnt in the 1st chap in D the units cancel eachother out but in A they wont its just a tip
IGCSEstudent201215. GPE at the top = 2 x 3 x 9.81 = 58.86 J. WD against friction = 5 x 7 = 35 J. 58.86 - 35 = 23.86 J. 23.86 = 1/2 x 2 x v^2. Solve for v.
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w10_qp_11.pdf can someone explain me how to do q18,q7(horizontal velocity isnt always constant),q9.thanks
Use v^2=u^2+2as. a=F/m. To find F, draw a free-body diagram on the 1 kg mass, and m will be 3 kg.http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w12_qp_11.pdf
Please help me with question no. 13.. I have no idea of what to do.
Thanks
22. Stress=F/A. F and A is given. E=stress/strain. strain=stress/E.http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w09_qp_11.pdf
help! question 22 and 26 please!
18. Use P=Fv.
7. When there's air resistance, the horizontal component decreases to 0. The vertical becomes constant (terminal velocity).
9. Use a suvat equation.
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