AS Physics P1 MCQs Preparation Thread.

[abruzzi]

momentum is M1V1-M2V2
that is 60m-40m=20m
elastic collision occurs as it is frictionless. M doubled as they stick to eachother so speed halves. 20/2=10
OR just use any value for mass and calculate. For example, mass=10kg. Then before collision momentum= (60*10)-(40*10)=200
after collision should also be 200kgms-1 so mass*velocity=200
as the 2 masses stick the mass is now 10+10 = 20kg
so velocity = 200/20=10

Thanks a lot

 

[abruzzi]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s10_qp_11.pdf
I need some help with qn no 16.. why is the answer D and not A?
Thanks

 

[marwa123]

Got it finally!
May Allah reward you for persevering with my thick-headed-ness (sorry physics is not my thing)
Thank you

hey there raweeha its marwa

 

[Raweeha]

hey there raweeha its marwa

Whadduuuup? Follow please?

 

[Mairaxo]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s10_qp_11.pdf
I need some help with qn no 16.. why is the answer D and not A?
Thanks

An easy way is to use the units method we learnt in the 1st chap in D the units cancel eachother out but in A they wont its just a tip

 

[Mairaxo]

Is the zeroth order considered a maxima?
And can you please explain no 24 from s10 p11?

its A. wavelength should be larger than the gap for diffraction. In a frequency in increasing so wavelength will decrease. hence less diffraction

 

[haha101]

can someone tell mei which variants from 11 12 13 are similar and which are different ?

 

[abruzzi]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w12_qp_11.pdf
Please help me with question no. 13.. I have no idea of what to do.

Thanks

 

[hellangel1]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w09_qp_11.pdf
help! question 22 and 26 please!

 

[Mairaxo]

quoted from other thread .... >>>help



1__Two springs P and Q both obey Hooke’s law. They have spring constants 2k and k respectively.
The springs are stretched, separately, by a force that is gradually increased from zero up to a
certain maximum value, the same for each spring. The work done in stretching spring P is WP,
and the work done in stretching spring Q is WQ.
How is WP related to WQ?
A WP =
1/4 WQ B WP =1/2 [1] WQ C WP = 2WQ D WP = 4WQ
i get C ... but the answer is B


2___A wave of amplitude a has an intensity of 3.0Wm–2.
What is the intensity of a wave of the same frequency that has an amplitude 2a
A_12 .. i used I>A^2 and still not coming

the qstns i anwered in the other post. For the image last question - 1st find the current. total R=7.5 then 2/7.5=0.26A. as it is parallel circuit current gets divided so 0.26/2=0.13 or 2/15 for easier calculation. then find V across X. V=IR = (2/15)*5 = 2/3V
then find V across Y. (2/15)*10 = 4/3V
potential diff is the diff between both V so 4/3 - 2/3 = 2/3

 

[Mairaxo]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w09_qp_11.pdf
help! question 22 and 26 please!

Q22- E=F*l/A*extension
A= (2.5*10^-4)^2 * pi
then substituting all values find l/extension. then find its reciprocal. then *100 to get %.
Q26- d=1/N. N=300000 per m
1/N=n*lambda
n will be 7 then times 2 u get 15

 

[abruzzi]

An easy way is to use the units method we learnt in the 1st chap in D the units cancel eachother out but in A they wont its just a tip

Yeah.. that makes sense. Thanks

Please help me with the other question that I have asked..

 

[Rahma Abdelrahman]

15. GPE at the top = 2 x 3 x 9.81 = 58.86 J. WD against friction = 5 x 7 = 35 J. 58.86 - 35 = 23.86 J. 23.86 = 1/2 x 2 x v^2. Solve for v.

IGCSEstudent2012
Check this

 

[IGCSEstudent2012]

IGCSEstudent2012
Check this

thanks :* Rahma Abdelrahman

 

[itallion stallion]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w10_qp_11.pdf can someone explain me how to do q18,q7(horizontal velocity isnt always constant),q9.thanks

 

[h4rriet]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w10_qp_11.pdf can someone explain me how to do q18,q7(horizontal velocity isnt always constant),q9.thanks

18. Use P=Fv.
7. When there's air resistance, the horizontal component decreases to 0. The vertical becomes constant (terminal velocity).
9. Use a suvat equation.

 

[h4rriet]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w12_qp_11.pdf
Please help me with question no. 13.. I have no idea of what to do.

Thanks

Use v^2=u^2+2as. a=F/m. To find F, draw a free-body diagram on the 1 kg mass, and m will be 3 kg.

 

[h4rriet]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w09_qp_11.pdf
help! question 22 and 26 please!

22. Stress=F/A. F and A is given. E=stress/strain. strain=stress/E.
26. Use dsin90=nxlambda and multiply that times 2 (the other 90 degrees) and add 1 (the middle maximum).

 

[itallion stallion]

18. Use P=Fv.
7. When there's air resistance, the horizontal component decreases to 0. The vertical becomes constant (terminal velocity).
9. Use a suvat equation.

i am using 2as=v2-u2 for 9 but cant get the answer.rest is understood.thanks

 

[h4rriet]

i am using 2as=v2-u2 for 9 but cant get the answer.rest is understood.thanks

Here's a way of doing it: s=u^2/2a. Assume that u = 300 and a = 50. s will then = 900. Increasing 300 by 20% will make it 360. If a stays the same, s = 1296. 1296/900=1.44.