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*Biology Paper 5 tips*

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Has there been any question to draw graphs and error bars? If yes then please be kind enough to post them. Thanks
There was just one, i dont remember the variant.
All you have to know is how to plot a graph and how to find the standard error. (It is standard deviation/underoot n)
That value you will have to plot above and below the point, you know like you do in physics. For instance, you get an error of 5. You that means your value will be +-5. I hope youre getting this.
 
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There was just one, i dont remember the variant.
All you have to know is how to plot a graph and how to find the standard error. (It is standard deviation/underoot n)
That value you will have to plot above and below the point, you know like you do in physics. For instance, you get an error of 5. You that means your value will be +-5. I hope youre getting this.


Yups got it Thanks alot (Y)
 
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Im sorry for a late reply.
It depends on the values. You see, in a graph with continuous data, some values may have overlapping bars and some might not. But just know this.
If error bars overlap, no significant difference, if they dont, there is significant difference and null hypothesis will have to be rejected. --> its a rule.
THANKS MAN!!!!! SUPERB :p
 
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Please help me in question 3 how did they found the Expected value ?? and degree of freedom?? and the probability of the values is always 0.05 why this time its is 0.001 ??
PLEASE HELP ME
The question paper link
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Biology (9700)/9700_w07_qp_5.pdf
And the mark scheme
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Biology (9700)/9700_w07_ms_5.pdf
There are 3 samples (grazed for 2 years ungrazed, for 10 years andungrazed for 30 years) so degree of freedom is n-1= 3-1 =2
secondly, I think they are accepting 0,05 probabilty. However, someone else might give a better answer.
 
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Please help me in question 3 how did they found the Expected value ?? and degree of freedom?? and the probability of the values is always 0.05 why this time its is 0.001 ??
PLEASE HELP ME
The question paper link
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Biology (9700)/9700_w07_qp_5.pdf
And the mark scheme
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Biology (9700)/9700_w07_ms_5.pdf

There are 3 samples (grazed for 2 years ungrazed, for 10 years andungrazed for 30 years) so degree of freedom is n-1= 3-1 =2
secondly, I think they are accepting 0,05 probabilty. However, someone else might give a better answer.

For b) ii) The explanation to answer is: Our Chi-Square value is 39.8 which is a much much larger value than the one given in row 2( i.e in the row of degree of freedom '2') of probability 0.05(since its a critical one). That means our value is way over the right side and thus the answer is 0.001(since it is on the extreme right and last of the probabilities).

AND for iii) Since our value is greater the difference is significant and is due to some other factor which you can go through from the marking scheme.

I hope I make some sense
 
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I have a few questions.

What would be a reason for anomalous value in an experiment?
Why is replicating data important?
Reason for anomalous value basically depends upon the question. If the question is about chromosomes, anomalous value might have occured due to a mutation or an abnormal division. Look for the question for clues
 
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For b) ii) The explanation to answer is: Our Chi-Square value is 39.8 which is a much much larger value than the one given in row 2( i.e in the row of degree of freedom '2') of probability 0.05(since its a critical one). That means our value is way over the right side and thus the answer is 0.001(since it is on the extreme right and last of the probabilities).

AND for iii) Since our value is greater the difference is significant and is due to some other factor which you can go through from the marking scheme.

I hope I make some sense
how is the expected calculated?
 
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Can someone please provide me with the text of the original post? Atm when I copy it and paste it the black background is also copied and I can't print that. Any help would be most welcome.

Thank you very much
 
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If I am not wrong, Validity depends upon standard deviataion and T tests and Chi Test is concerned with reliability ? Aint it?
No, first dude was right.
Reliability is such that when you repeat the experiment, your results are reliable enough to get the same results next time. They're valid only from tests.
Does that make sense?
 
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Can someone please provide me with the text of the original post? Atm when I copy it and paste it the black background is also copied and I can't print that. Any help would be most welcome.

Thank you very much

You just copy the whole text and paste it in WORD using unformatted text paste. If you don't know how, there's a paste button on top of the WORD menu, click on the little arrow below it, then click special paste and there should be 'unformatted text'. :)
 
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