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hahahaha cn u solve it??
Use the equation of motion d = ut + 0.5at^2
equation 1 : 40 = 12u + 72a
equation 2 : 80 = 18u + 162a
[I added the distances, so that initial speed of both equations will be same]
now solve these simultaneously, and you will get 0.37 m/s^2 as the answer.