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Physics: Post your doubts here!

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A moving body undergoes uniform acceleration while travelling in a straight line between points
X, Y and Z. The distances XY and YZ are both 40 m. The time to travel from X to Y is 12 s and
from Y to Z is 6.0 s.

What is the acceleration of the body?


Ans is 0.37 ms-2
can you give the link of this question pls
 
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but y isn't the initial velocity 0?
lets see the motion in XY
initial velocity at x=v1
final velocity at y=v2
average velocity=distance/time
(V1+V2)/2=40/12 equation 1
simplifying it we get V1+V2=6.67

now consider motion in XZ
initial velocity at x=v1
final velocity=v3
V1+V2/2=(40+40)/(12+6)
simplifying it we get V1+V3=8.89 equation 2
subtract equation 1 from 2
i mean equation 2-equation 1
V1 is cancelled and we get V3-V2=2.22
since acceleration is constant so
acceleration in yz = acceleration in xz
= change in velocity/time
=2.22/6
=0.37


o_O Shamjhi ?
 
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lets see the motion in XY
initial velocity at x=v1
final velocity at y=v2
average velocity=distance/time
(V1+V2)/2=40/12 equation 1
simplifying it we get V1+V2=6.67

now consider motion in XZ
initial velocity at x=v1
final velocity=v3
V1+V2/2=(40+40)/(12+6)
simplifying it we get V1+V3=8.89 equation 2
subtract equation 1 from 2
i mean equation 2-equation 1
V1 is cancelled and we get V3-V2=2.22
since acceleration is constant so
acceleration in yz = acceleration in xz
= change in velocity/time
=2.22/6
=0.37


o_O Shamjhi ?
oh... thnx.... :unsure:
 
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physics dude :) its how the line of spectrum of hydrogen provides evidence for the existence of the descreet electron energy level in atoms :)
When an electron in an atom loses energy,radiations are emitted and the energy of the radiation is equal to the difference in the energy of the atom between its initial and final state.since the emitted radiation have definite energies or discrete wavelength so the energy levels are also discrete In an atom!
 
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