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thanks a lotThere are 4 C--H bonds and 2 O=O bonds broken. So calculate the energy absorbed for this:
4 * [C--H] + 2 [O=O] = 4 * 410 + 2 * 496 = 2632
There are 2 C=O bonds and 4 O--H bonds formed. So calculate the energy released:
2 * 740 + 4 * 460 = 3320
Now find the enthaply:
energy absorbed - energy released
= 2632 - 3320
= - 688 kJ/mol
So the answer is D.
but wait...why didn't we use the value of 'C=O in CO2' which is 805 as per the data booklet?