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Recent content by waleedsmz
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Physics: Post your doubts here!
Neither is easy. The problem with mathematics however is the very low gradient. I remember you could lose like 80 marks in physics and still have an A*. Maths gradient was about 35 if I remember. I'm not quiet sure though. I took both ALevels and my opinion is that physics would be a better... -
Mathematics: Post your doubts here!
Second part of the question is pretty easy, you just substitute with 2 in the given equation. You find minimum/maximum of something by differentiating it, and equating the derived formula to zero. Thus to find the minimum of the GRADIENT you need to differentiate dy/dx. This would be 1-8/x^3... -
Mathematics: Post your doubts here!
The equation itself is root(8x-x^2) so when it is squared, the root is just omitted and that's it. :) -
Physics: Post your doubts here!
K.E.(original) = 0.5mv^2... let it be 0.5, and the new one be 2 0.5mv^2 = 0.5, mv^2=1, v=root(1/m) similarly, new v = root(4/m) mv ( original ) = 1 root(m) mv ( new ) = 2 root(m) The new one is double the old one and therefore the increase is 100%. Notice that the more "formal" way of... -
Physics: Post your doubts here!
I'm sorry I'm already a graduate and I'm pretty sure we didn't take that. I hope someone else answers. :) -
Physics: Post your doubts here!
Could you be more specific, please? Link an example if you can. -
Physics: Post your doubts here!
2) The time period of the wheel is 0.02s. To show it clearly on an oscilloscope you'd need 0.01s/cm, which is B. 3) Large systematic error means that there is an error in the tools you're using for example, so it measures a completely different value from what you're trying to reach. This... -
Physics: Post your doubts here!
What exactly is your problem? Be a little more specific and it'd be great if you could link an example. -
Physics: Post your doubts here!
Why don't you guys link the paper? Be a little helpful. -
Mathematics: Post your doubts here!
As for 7ii) You have the derivative of the equation, also known as "y dash". To get the original curve you simply need to integrate. So... 5 becomes 5x and -8/x^2 becomes +8/x. However, there is the constant of integration, so the final thing is. y = 5x + 8/x + c. Point P is on the curve thus... -
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Mathematics: Post your doubts here!
Similar to the question above that one, you'd simply have to expand ( sec + tan ) ^2 sec^2 + 2sectan + tan^2 sec^2 + 2sectan + sec^2 - 1 What's the problem? -
Mathematics: Post your doubts here!
( s+c ) ( 1 - s c ) Expand the brackets: s + c - s^2 c - s c^2 Using identities s^2 + c^2 =1 s + c - (1 - c^2 )c - s(1-s^2) Do the calculations, it'd give the required form. -
Mathematics: Post your doubts here!
The cosine function can take up any value from -1 to 1. But since it is squared ( k = 2 ) , then it can take any value from 0 to 1. Therefore, to find the first limit, you substitute with 0 , it gives you 3. The other limit, you substitute with 1, it gives you 3-4 =-1. -
PLEASE HELP ME! SOMEONE GUIDE ME!
The only thing I can give to you is that you HAVE TO DO IT! It's not really a matter of choice. You want that A*, then work to get it. Pretty simple.