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  1. waleedsmz

    Physics: Post your doubts here!

    Neither is easy. The problem with mathematics however is the very low gradient. I remember you could lose like 80 marks in physics and still have an A*. Maths gradient was about 35 if I remember. I'm not quiet sure though. I took both ALevels and my opinion is that physics would be a better...
  2. waleedsmz

    Mathematics: Post your doubts here!

    Second part of the question is pretty easy, you just substitute with 2 in the given equation. You find minimum/maximum of something by differentiating it, and equating the derived formula to zero. Thus to find the minimum of the GRADIENT you need to differentiate dy/dx. This would be 1-8/x^3...
  3. waleedsmz

    Mathematics: Post your doubts here!

    The equation itself is root(8x-x^2) so when it is squared, the root is just omitted and that's it. :)
  4. waleedsmz

    Physics: Post your doubts here!

    K.E.(original) = 0.5mv^2... let it be 0.5, and the new one be 2 0.5mv^2 = 0.5, mv^2=1, v=root(1/m) similarly, new v = root(4/m) mv ( original ) = 1 root(m) mv ( new ) = 2 root(m) The new one is double the old one and therefore the increase is 100%. Notice that the more "formal" way of...
  5. waleedsmz

    Physics: Post your doubts here!

    I'm sorry I'm already a graduate and I'm pretty sure we didn't take that. I hope someone else answers. :)
  6. waleedsmz

    Physics: Post your doubts here!

    Could you be more specific, please? Link an example if you can.
  7. waleedsmz

    Physics: Post your doubts here!

    2) The time period of the wheel is 0.02s. To show it clearly on an oscilloscope you'd need 0.01s/cm, which is B. 3) Large systematic error means that there is an error in the tools you're using for example, so it measures a completely different value from what you're trying to reach. This...
  8. waleedsmz

    Physics: Post your doubts here!

    What exactly is your problem? Be a little more specific and it'd be great if you could link an example.
  9. waleedsmz

    Physics: Post your doubts here!

    Why don't you guys link the paper? Be a little helpful.
  10. waleedsmz

    Mathematics: Post your doubts here!

    As for 7ii) You have the derivative of the equation, also known as "y dash". To get the original curve you simply need to integrate. So... 5 becomes 5x and -8/x^2 becomes +8/x. However, there is the constant of integration, so the final thing is. y = 5x + 8/x + c. Point P is on the curve thus...
  11. waleedsmz

    Mathematics: Post your doubts here!

    You're welcome. : )
  12. waleedsmz

    Mathematics: Post your doubts here!

    Similar to the question above that one, you'd simply have to expand ( sec + tan ) ^2 sec^2 + 2sectan + tan^2 sec^2 + 2sectan + sec^2 - 1 What's the problem?
  13. waleedsmz

    Mathematics: Post your doubts here!

    ( s+c ) ( 1 - s c ) Expand the brackets: s + c - s^2 c - s c^2 Using identities s^2 + c^2 =1 s + c - (1 - c^2 )c - s(1-s^2) Do the calculations, it'd give the required form.
  14. waleedsmz

    Mathematics: Post your doubts here!

    The cosine function can take up any value from -1 to 1. But since it is squared ( k = 2 ) , then it can take any value from 0 to 1. Therefore, to find the first limit, you substitute with 0 , it gives you 3. The other limit, you substitute with 1, it gives you 3-4 =-1.
  15. waleedsmz

    PLEASE HELP ME! SOMEONE GUIDE ME!

    The only thing I can give to you is that you HAVE TO DO IT! It's not really a matter of choice. You want that A*, then work to get it. Pretty simple.
  16. waleedsmz

    AS Physics P1 MCQs Preparation Thread.

    I'm sorry but could you explain this formula? Like what the letters represent and stuff, because it seems unfamiliar. What are the a, x , D and d in this situation? Thanks.
  17. waleedsmz

    AS Physics P1 MCQs Preparation Thread.

    I believe the answer is C because as the kinetic energy increases, the change in speed required to do this increase actually decreases. This is due to kinetic energy being proportional to the square of the velocity. Let me explain... Increase in K.E. ----> Increase in speed 1-->10...
  18. waleedsmz

    AS Physics P1 MCQs Preparation Thread.

    I'm not really sure about 9 and 13... 14: At the maximum height , there is only the horizontal velocity acting on the particle ( Vcos45 ). So... 27: The electric field of a particle ( Q ) is the force done BY the particle on a unit charge ( divided by q ). Although they basically have the...
  19. waleedsmz

    AS Physics P1 MCQs Preparation Thread.

    Umm... I think the wavelength is actually 15/2 not 15 x 2 since you have 5 nodes ( 2 wavelengths )...
  20. waleedsmz

    AS Physics P1 MCQs Preparation Thread.

    It certainly does mean something. The rigid box keeps the spring from extending beyond a fixed point. This is done because the question wants a high sensitivity for small masses and a low sensitivity for higher masses. It will be sensitive until the top spring with low constant comes in contact...
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