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  1. not.maria

    Chemistry: Post your doubts here!

    the first four ionization energies are for 2p4 electrons the fifth and 6th are for 2s2 the last one is for 1s2 hence such a BIG difference because it is closest to the nucleus the closer electron to the nucleus the more the IE
  2. not.maria

    Chemistry: Post your doubts here!

    we for the first four IE the difference is roughly 2000 between the 4th and 5th there is a difference of 3550.but the principal quantum number is still the same i.e the principal quantum no is 2. the distance between 2p and 2s is small.while distance between 2s and 1s is large
  3. not.maria

    Chemistry: Post your doubts here!

    I dont get it. wont the equilibrium shift to the right hand side if ammonia i.e product is removed?:confused:
  4. not.maria

    Chemistry: Post your doubts here!

    Please someone help me out in this! I am clueless
  5. not.maria

    Chemistry: Post your doubts here!

    the examiner report gave a pretty nice explanation: Some candidates might have found it easier to recognise A as correct if they had rewritten the equation using familiar substances, for example, CH4(g) →C(g) + 4H(g). Dividing ΔH by 4 will give a value for the C-H bond energy.
  6. not.maria

    Chemistry: Post your doubts here!

    kc =(Product)/(reactant) =(x)(x)/(1-x)(1-x) do you get it ?
  7. not.maria

    Chemistry: Post your doubts here!

    this one also look at my post again.I edited it. the pics were not uploading
  8. not.maria

    Chemistry: Post your doubts here!

    look at the table
  9. not.maria

    Chemistry: Post your doubts here!

    q9 q 11 assume the moles used up were x. so u have equation 4= x^2/(1-x)^2 taking square roots on both sides we have 2=x/(1-x) 2-2x=x 2/3 =x since volume is not mentioned you can assume it to be 1 dm^3
  10. not.maria

    Chemistry: Post your doubts here!

    http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Chemistry%20(9701)/9701_s12_qp_11.pdf Can someone explain Q 2, 9, 13 ,14, 22 and 36 Thanks!
  11. not.maria

    Physics: Post your doubts here!

    got it.
  12. not.maria

    Physics: Post your doubts here!

    no i mean why do we take fringe separation to be the distance from the middle of a dark fringe to the middle of the other dark fringe
  13. not.maria

    Physics: Post your doubts here!

    Thanks . I got the right ans this time.:) but could you also give me a reason why we take that distance ?
  14. not.maria

    Physics: Post your doubts here!

    can anyone please explain how to solve q29 http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20(9702)/9702_s11_qp_12.pdf
  15. not.maria

    and u are since 2014 0.0

    and u are since 2014 0.0
  16. not.maria

    Physics: Post your doubts here!

    Thanks alot! this is helping me soo much:) however q18 19 20 were for this paper: http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w10_qp_12.pdf :)
  17. not.maria

    Physics: Post your doubts here!

    Please can anyone explain: q8 and q 21 http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20(9702)/9702_w10_qp_12.pdf And also can anyone kindly help me out in this?
  18. not.maria

    Physics: Post your doubts here!

    for q15 if the depths of water are equal by the end then the gain in height of water in the second tank should be h/2. since the tanks are identical each tank would have equal volumes so the mass of water that has moved to the other tank should be m/2. since mass is directly proportional to...
  19. not.maria

    Physics: Post your doubts here!

    http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20(9702)/9702_s09_qp_1.pdf can anyone please explain q18 19 and 20 Thanks!
  20. not.maria

    Physics: Post your doubts here!

    for q37 find the current in the ammeter for each circuit diagram by assuming random values for emf and resistance.I took emf 6V and Resistance 12 ohm for each resistor for A the effective resistance will be 12+12=24 ohm using V=IR , I comes 0.25 A For B the current does not pass through the...
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