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Physics: Post your doubts here!

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Ahmed H. Al-Neel said:
can anyone help me with question 15,21,23,35 ?
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s13_qp_11.pdf
Click to expand...
15)IDK

21)
pressure in liquids=hxdensityxg
pressure due to oil=Xx830x9.81
pressure due to water=(2000-x)x10000x9.81
since pressure et bottom =17.5MPa
[Xx830x9.81]+[(2000-x)x10000x9.81]=17.5MPa
solve x to give 1270 as the final answer

23)
F = kx so x = F/k
For A : x = 4/k
For B : x = 3/k
For C : x = 3k
For D : x = 8/3k
So here constant k is either being multiplied or divide, hence we take k as 1 if we would have addition or subtraction included, we take k as zero
Now put 1 instead k .. A = 4, B = 3, C = 3, D = 2.5 so A is the answer :)

35)IDK
 
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Anonymous981 said:
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_11.pdf
Question number 15
Click to expand...
untitled-png.44397
 
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Ahmed H. Al-Neel said:
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w10_qp_12.pdf
questions 7,9,22,26,27,34 please!
Click to expand...
7)
Acceleration upwards is always -9.81 and downwards 9.81. As upward motion is positive, + multiplied ny - gives you -9.81. Vice versa with downward motion. - multiplied with +9.81. The magnitude stays the same as long as air resistance is neglected, and the sign depends on which direction you take as positive.

9)
initial momentum of the ball is 2mv before collision... if collision was perfectly elastic one, all the momentum would have been gained by the ball... and this would have made the change in the momentum equal to 4mv.. 2mv-(-2mv)... now it is given that collision is inelastic, it will lose some of its momentum to the wall.. so now change in momentum will be less than 4mv but cant be less than the initial momentum... so the answer is C.

22)
because since k is low for the first spring, the box will prevent it from breaking by over extending. Hence A

26)
We know that distance between two minima is given by λ/2 (example, distance b/w T and S is λ/2)
We also know that Microwave travels with the speed of light c i.e is 3 * 10^8 m/s
Given distance b/w each minima is 15 mm so total distance from T to P would be 15 * 4 = 60 mm

Now distance b/w:
T and S = λ/2,
S and R = λ/2
R and Q = λ/2
Q and P = λ/2
and them you get 2λ
so 2λ = 60*10^-3
hence λ = 0.03 m

We know that c = f * λ
So f = c / λ
f = ( 3 * 10^8 ) / ( 0.03 )
f=10GHz

27)
Let the distance between the double slit and the screen be 1m initally.
When the distance is increasd BY 2m the NEW distance is 3m.
Using the formula:
Wavelength= (fringe seperationx distance between the double slits)/ distance between the screen and the slits.
Wavelenght=600nm=600x10^-9m.
Fringe seperation= 3mm= 3x10^-3m
Distance between screen and slits= 3m (1+2)
Distance between the double slit=?
Put these values in the formula, the final answer is 6x10^-4m =0.6mm
Hence the answer is B.

34)
voltage decreases linearly so its supposed to be B : as rho increases, there would be more steepness in graph
 
Ahmed H. Al-Neel

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Thought blocker said:
7)
Acceleration upwards is always -9.81 and downwards 9.81. As upward motion is positive, + multiplied ny - gives you -9.81. Vice versa with downward motion. - multiplied with +9.81. The magnitude stays the same as long as air resistance is neglected, and the sign depends on which direction you take as positive.

9)
initial momentum of the ball is 2mv before collision... if collision was perfectly elastic one, all the momentum would have been gained by the ball... and this would have made the change in the momentum equal to 4mv.. 2mv-(-2mv)... now it is given that collision is inelastic, it will lose some of its momentum to the wall.. so now change in momentum will be less than 4mv but cant be less than the initial momentum... so the answer is C.

22)
because since k is low for the first spring, the box will prevent it from breaking by over extending. Hence A

26)
We know that distance between two minima is given by λ/2 (example, distance b/w T and S is λ/2)
We also know that Microwave travels with the speed of light c i.e is 3 * 10^8 m/s
Given distance b/w each minima is 15 mm so total distance from T to P would be 15 * 4 = 60 mm

Now distance b/w:
T and S = λ/2,
S and R = λ/2
R and Q = λ/2
Q and P = λ/2
and them you get 2λ
so 2λ = 60*10^-3
hence λ = 0.03 m

We know that c = f * λ
So f = c / λ
f = ( 3 * 10^8 ) / ( 0.03 )
f=10GHz

27)
Let the distance between the double slit and the screen be 1m initally.
When the distance is increasd BY 2m the NEW distance is 3m.
Using the formula:
Wavelength= (fringe seperationx distance between the double slits)/ distance between the screen and the slits.
Wavelenght=600nm=600x10^-9m.
Fringe seperation= 3mm= 3x10^-3m
Distance between screen and slits= 3m (1+2)
Distance between the double slit=?
Put these values in the formula, the final answer is 6x10^-4m =0.6mm
Hence the answer is B.

34)
voltage decreases linearly so its supposed to be B : as rho increases, there would be more steepness in graph
Click to expand...
thanks alooot i just forgot to ask u earlier, can u also do q.)25 ?
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w10_qp_12.pdf
 
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Ahmed H. Al-Neel said:
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_12.pdf
questions 16 and 17 please!
Click to expand...
16)
You know that the weight always acts at the centre.. so lets assume the distance XY to be 1m.
The horizontal component of force F is Fsin30.

Sum of clockwise moments = sum of anti-clockwise moments
0.5 x 10 = 1 x Fsin30
F = 10N

17)
The tension (4N) is the same on both sides; XY and XZ.
First, we have to find the angle YXP
Sin theta = 40/50
theta = 53

Next, find the horizontal component of the tension:
= 4cos53
= 2.4N

The same horizontal component will be experienced on XZ

Hence, 2.4 X 2

=> 4.8 N
 
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