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  1. Khan_971

    Mathematics: Post your doubts here!

    Q2. You should draw a tree diagram for this. Then you will understand. See, the questions if you analyze asks for everything except Males NOT watching the kids. Hence add up all probabilities except Males watching. it is 5/6. if you try to answer numerically, it usually doesnt come right. Q3...
  2. Khan_971

    Mathematics: Post your doubts here!

    There are 3 different objects which can be put in any order. hence 3!
  3. Khan_971

    Mathematics: Post your doubts here!

    im gonna do this paper now and will try to get back to you.
  4. Khan_971

    Mathematics: Post your doubts here!

    The 12s, 4s are the no.of arrangements possible of those 4 letters.
  5. Khan_971

    Mathematics: Post your doubts here!

    Done. Look up.
  6. Khan_971

    Mathematics: Post your doubts here!

    i'll solve both parts simultaneously the simplest way is to write possibilities alphabetically .1 EEOP . . 12 . . [ 4!/2! ] .2 EEOS . . 12 .3 EEPS . . 12 .4 EESS . . . 6 . . [ 4! / (2!*2!) ] .5 EOPS . . 24 . . [ 4! ] .6 EOSS . . 12 .7 EPSS . . 12 .8 ESSS . . . 4 . . [ 4! / 3! ] .9 OPSS ...
  7. Khan_971

    Mathematics: Post your doubts here!

    since there are 4 numbers. and each order matters. 4!= 24 Since there is no number greater than 5412, this is easy.
  8. Khan_971

    Mathematics: Post your doubts here!

    p63 is really a difficult one. but GT has 38+ as A :O
  9. Khan_971

    Mathematics: Post your doubts here!

    I've had same trouble. I just subtracted P(male who dont watch) from 1 to get 5/6 as the 5/6 means the prob that its a female, any gender who watches and a watching female. Only males who dont watch are left out. If you find a way through. let me know too :)
  10. Khan_971

    Statistics P6 Help needed

    Go for the books first. Try out a FEW starting questions and some of the last. Check yourself for clear concepts. Then go for the past papers. Backwards from 2011 will be good.
  11. Khan_971

    Answer milgaya?

    Answer milgaya?
  12. Khan_971

    Mathematics: Post your doubts here!

    I assume that there cant be 0 students in a school. either way. I take at least 1 in a school. so therfore to find the midpoint (100+1)/2 try doing this way for all the columns. :)
  13. Khan_971

    Mathematics: Post your doubts here!

    Well how will you calculate the mean using the table then?
  14. Khan_971

    Mathematics: Post your doubts here!

    Well if you check the normal distribution. There's no value smaller than 0.5. So as in the case you just said. it has to be subtracted from 1. PROVIDED that if Z<any negative value for example.
  15. Khan_971

    Mathematics: Post your doubts here!

    in part b. 2 people (couple) have booked their places. so assume 2 people and 2 seats are out . leaving 2 seats to choose from 8 people. therfore 8C2 = 28. Probability of this will be 28/ALL possible combinations = 28/210 = 2/15
  16. Khan_971

    Mathematics: Post your doubts here!

    Could you make it clear? plus the caps lock is not recommended.
  17. Khan_971

    Mathematics: Post your doubts here!

    3 youngest to be chosen means 3C3. Which means there are 7 people left to compete for 1 place. therefore 7C1 = 7. divide that by the total possible ways (210) to get 1/30
  18. Khan_971

    Mathematics: Post your doubts here!

    The 1st interval is about 1-100. therfore mid class value = (100+1)/2 2nd interval is 101-150, therfore (101+150)/2 = 125.5 And so on..
  19. Khan_971

    "A-Level exams are finally going to get harder" -CIE

    CIE is more (not entirely, mind you) of an international standard than Edexcel, which is based alot in the UK. You can go through this . 8th comment. This is more of a pointless argument just because it was not specified which board or all. And this won't probably happen till when a new syllabus...
  20. Khan_971

    A2 Vectors formula sheet?

    AOA, Well I found it finally. U can have them here: http://www.xtremepapers.com/community/threads/a2-vectors-notes.14125/
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