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  1. Khan_971

    Mathematics: Post your doubts here!

    Well. It depends on the intervals in the group data. If an Upper Boundary of the Interval is the same value as the Lower Boundary of the next interval, then there's no need to add/subtract .5 to the corresponding boundaries. I.e, 0-100, 100-200 But if it is 1-99, 100-149. Then subtract .5 from...
  2. Khan_971

    Chem p4 and Math p6. And I am going berserk!

    I have a good grip, not excellent though on p6. Chem p4, other than app. booklet. Are you guys going through anything? Section B can be a problem for me.
  3. Khan_971

    Mathematics: Post your doubts here!

    Well that's a surprising question. Student, though. :)
  4. Khan_971

    Mathematics: Post your doubts here!

    I love these questions. They are the easiest, that's why. :P Within 12 g implies the least is 20-12 = 8 and highest = 20+12 =32 so P(8<X<32) P( 8-20 / σ <Z< 32-20 / σ) P(-12/σ <Z < 12/σ) Seems familiar? :D
  5. Khan_971

    Mathematics: Post your doubts here!

    Nah. Im freaked out. p4 and p6. This is one pressure week :(
  6. Khan_971

    Mathematics: Post your doubts here!

    n.n? Yes. and day after tomorrow chem p4 as well! :@
  7. Khan_971

    Mathematics: Post your doubts here!

    that wierd symbol. ϕ is the fi. the function through which u have to go to the table :)
  8. Khan_971

    Mathematics: Post your doubts here!

    0/5 is the probability of GETTING a 2 in Bag B. 1 is the probability of not getting a 2 :)
  9. Khan_971

    Mathematics: Post your doubts here!

    U subtract the fi(1.0750 from 1. but since the sign outside is -ve, it reverses. It is a rule that P(a<Z<b) then fi(b)-fi(a) but if P(-a<Z<b). fi(a negative value) is 1-fi(the value). the minus is kicked out. See the normal distribution table page. it is written there as well therefore...
  10. Khan_971

    Mathematics: Post your doubts here!

    the method is : fi(1.629)- (1-fi(1.075)) therefore fi(1.629) + fi (1.075) -1 Just as the given expression.
  11. Khan_971

    Mathematics: Post your doubts here!

    2 Ps kicked out. 7 letters left including 2 S in first case, lets take 1 S. (so we wont count the other S) 5 letter to fill in other 3 places. 5C3 = 10 second case, 2 S chosen. 2 places left for 5 letters. 5C2 = 10 Final = 20.
  12. Khan_971

    Mathematics: Post your doubts here!

    In case it does not. PM me with the link and number of that question.
  13. Khan_971

    Mathematics: Post your doubts here!

    M2? woah. well that really wasnt in my knowledge. Maybe just multiply V with the expression of dv/dx i showed.
  14. Khan_971

    Mathematics: Post your doubts here!

    LOL I think im gonna crack xD Well yes you are right. but you cant try to see if it guarantees the correct answer. u have to do it this way else: They are in serial, (Bag A, B, C) P(2, not 2, 2) + P(8, Not 8, 8) + P(Not 8 , 8,8) + P(8,8, Not 8) part ii is conditional probability, P(2,not 2,2)...
  15. Khan_971

    Mathematics: Post your doubts here!

    Didnt I clear this?
  16. Khan_971

    Mathematics: Post your doubts here!

    But where was this from? u just had to multiply what i gave with V right?
  17. Khan_971

    Mathematics: Post your doubts here!

    BTW 20C7 IS 12!/7!5! :P
  18. Khan_971

    Mathematics: Post your doubts here!

    Part a is either 52C8 or 52P8. If each picture is different then its P. b) 12C3 * 20C3 * 20C2 OR P as im not sure about the pictures being different.
  19. Khan_971

    Mathematics: Post your doubts here!

    Ok so the table will be like this, 5 girls and 3 boys , and a team of 4. so at minimum we can have 3 guys and 1 girl. B- boy. G- girl BBBG = 5C1 BBGG= 3C2*5C2 BGGG= 3C1*5C3 GGGG= 5C4 Add them up to get total possibilities. Divide each value above by this Total possibilities to get its...
  20. Khan_971

    Mathematics: Post your doubts here!

    Here. Comment #3264
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