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Mathematics: Post your doubts here!
attached a file. see if that's what you need. -
Mathematics: Post your doubts here!
Already cleared before. check the previous pages. -
Mathematics: Post your doubts here!
I mentioned somewhere a few minutes ago that this will lead to 2fi(a/root21)-1 = .5 fi(a/root21) = 1.5/2 fi(a/root 21) = .75 -
Mathematics: Post your doubts here!
a column has 8 places. 2 holes to get in. 8C2. Im not sure about the toher 2 parts. Mind telling me which paper is this from? -
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Mathematics: Post your doubts here!
Draw a tree diagram. 1-P (0 boys) is your answer -
Mathematics: Post your doubts here!
Where is this question? because the way u wrote it, looks unusual. -
Mathematics: Post your doubts here!
2^12 implies each coin in 2 ways. It wont matter if its heads or tails. but we do require a specific number :) -
Mathematics: Post your doubts here!
He meant ke look. if it is (-y<Z<y). Where y is any number Then the prob. will be fi(y) - (1-fi(y)) [since fi(-y) will be 1-fi(y) open the brackets, 1 becomes negative, the fi's add up 2fi(y)-1 is the final thing. -
Mathematics: Post your doubts here!
the N (x,y) means x is the Mean (that miuw symbol) and y is the Variance, (sigma squared). havent u done normal distribution? Subtract mean from 33+a and 33-a, divide by standard deviation?? -
Mathematics: Post your doubts here!
Ok well u know we simply cant leave spaces in a histogram. so thats why u have to make a connection between the intervals. In O levels u can recall adding .5 to the upper boundary and subtracting .5 from the lower boundary. Meaning first interval will be .5-20.5. 2nd will be 20.5-30.5. and so... -
Mathematics: Post your doubts here!
WOOPS. My bad. thanks for checking. since there are 7 same heads and 5 same tails. Remember if letter/objects are repeated u divide the total possible arrangments by n!, where n is the number of times it is repeated. so 12 coins, 12! 7 heads, so divide by 7!. 5 tails so divide by 5! -
Mathematics: Post your doubts here!
Im gonna try my best. Okay so Brown can only take 1 of the 3 seats right? 3C1 = 3 Lin will only get behind a student. So take two fingers and place them on two side-by-side seats. assume brown take the front seat at the right corner. Count all positions Lin can sit in: 10 Only 1 of 5 students... -
Mathematics: Post your doubts here!
500+ means 513, 531, 561, 563 do the same for the rest. Need I say more? -
Mathematics: Post your doubts here!
first part is direct 4!. 2nd part u gotta write down all possible combinations. I already showed the third part -
Mathematics: Post your doubts here!
2 Possibilities of outcome, Head or tail. since twelve coins, arrangements = 2*2*2*2*2*2*2*2*2*2 = 2^12 part 2 is binomial expansion. Let X be no. of heads. and since it is unbiased Prob. of getting heads (p) or tails (q) 20C7 * (.5)^7 * (.5)^5 -
Mathematics: Post your doubts here!
Correct! look the the question. they asked females or anyone who watches or both! (both already comes in when you add P(female)+ P(anyone who watches since it means both genders). U can add these up OR since the only people left out are people who DONT watch, their probability = 5/30. Subtract... -
Mathematics: Post your doubts here!
Draw a probability distribution table. Since the rest except 0 have equal probability, let it be x Let X be the random variable and P(X) being its probability X....-2...-1...0..........1...2...3...4...5 p(x).x...x....1/10......x....x...x...x..x Since total probability is always 1, 7x + 1/10=... -
Mathematics: Post your doubts here!
Part a i. Well duh there's no repeating. so just 4! = 24 arrangements. Part a ii. Well U have to work on this. an odd number will have 1,3,5 in the end. 5 or 6 in the 1st digit and any of the 4 as 2nd digit. use this to write down possible combinations. b. NOT next to each other has many... -
Mathematics: Post your doubts here!
Tree diagram. You do know conditional probablility right. It will be P( It was in his pencil case {.7} / he finds it when he looks for it {.7 + .3*.2} )