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Mathematics: Post your doubts here!
Part 4...hmmm. okay see there will normally be 4! arrangements if 4 diff. colors are used. since 2 are the same, we make it 4!/2!. there are 6 colors in total, AND since u have to choose 1 peg of a specific colour only, 6x 5C2 therefore, 4!/2! arrangements * 6 colors * 5C2 pegs of diff colours... -
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Mathematics: Post your doubts here!
CC usually kicks in when theres a ≥ or <= of some value. :)when theres 'at least' or 'should not be greater than' -
Mathematics: Post your doubts here!
See. 2 people getting odd numbers froma total of 10 mugs 1st person is who we'll deal with: can get 1 ,3 ,5 ,7 ,9 Possibilities: 10C1, 10C3, 10C5, 10C7, 10C9 add them up to get total arrangements. -
Mathematics: Post your doubts here!
Usually there's the phrase USE a Suitable approximation :) -
Mathematics: Post your doubts here!
Its gonna be tough writing here. I suggest khanacademy.org or your teacher :) -
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Mathematics: Post your doubts here!
Pals_1010 I got it. if theres a 5 digit number. and without repetition. it will be 5! as all those 5 numbers can be either way. 5! + 72 = 192 -
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Mathematics: Post your doubts here!
Lower boundary, 20-12 = 8, upper 20+12 = 32. P( 8<X<32) =.94 -
Mathematics: Post your doubts here!
Write it down. 4000-4999. 4P3 5000-5999: 4P3 6000-6999: 4P3 total : 72? -
Mathematics: Post your doubts here!
I think u have to take (n+1)/2 -
Mathematics: Post your doubts here!
3 diff colors: Red,red,not red, not red = 2C2 * (5 * 2C1) x 4!/2! since 4 pegs and 2 are same Since the rest 5 colors have 2 pegs each. Total= (5*2C1) * 4!/2! * 6 = 720 -
Mathematics: Post your doubts here!
u have to inter-connect the intervals. First Interval: 1-100, 101-150. subtract .5 from lower, add to higher. 1st interval: .5-100.5, 100.5-150.5 Mid-value = .5+100.5 / 2 = 50.5 and so on -
Mathematics: Post your doubts here!
6C4 * 4!. Or it can be 6P4. If orders are important (prizes in some cases0 , Permutation is to be used. If not (order does not matter, example choosing people for commitee,etc) In this question. order is important -
Comment here the paper's link and question number :)
Comment here the paper's link and question number :)- Khan_971
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Mathematics: Post your doubts here!
I am not so sure, :/ do u Live in Khobar/Dammam? -
Mathematics: Post your doubts here!
Mean= Σ(x − a)/n +a where a is a constant Variance Σ(x − 25)^2 / n - [mean]^2 -