• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Search results

  1. daredevil

    Chemistry: Post your doubts here!

    ethanoicc acid?? bcz 2 organic molecules will be needed to balance out the 2+ valency of Ca
  2. daredevil

    thanku 2 :)

    thanku 2 :)
  3. daredevil

    Chemistry: Post your doubts here!

    i am getting a confidence boost by solving these questions :P and i need it for tuesday :P so yuppp i'm on FiiRREE!! :P
  4. daredevil

    Chemistry: Post your doubts here!

    the mass of nickel in the coin is 20% of 10 = 2 g calculate the no. of moles of Ni in the coin: - 2/58.7 multiply that no of moles with the avogadro's constant (6*10^23) the answer u get is 2.05*10^22
  5. daredevil

    Chemistry: Post your doubts here!

    all kinds i think
  6. daredevil

    Chemistry: Post your doubts here!

    the answer is C. make up a Hess's triangle. use x to be the emthalpy of conbustion of C used by the student.put in the enthalpies of combustion of ethane and hydrogen. balance the triangle and multiply the enthalpies accordingly. the resulting equation will be: - 3(-286) +2x - (-1560) = -158...
  7. daredevil

    Chemistry: Post your doubts here!

    yh my teacher told us to do it in our head and practice that way bcz we need to complete our paper and we don't have time for drawing but i can almost never solve such questions w/o drawing first so i just draaw up a rough displayed formula quickly to help clear it out.
  8. daredevil

    Chemistry: Post your doubts here!

    Q1's answer is C. from the data u can infer that 50 cm3 of O2 was used to burn 10cm3 of hydrocarbon (CxHy) make up an equation for the unknown hydrocarbon for ur aid and u'll c that 1 mol of CxHy requires 5 moles of O2 to produce 3 mol of CO2. 6 O go into the CO2 and the remaining 4 (from 5 O2)...
  9. daredevil

    Chemistry: Post your doubts here!

    solid?
  10. daredevil

    Chemistry: Post your doubts here!

    okay woaaah!! :O umm... i think if i took the time of drawing out the whole friggin structure i cud maybe get the hang of it - or maybe not :P i remember our sir made us do it in class and after a little while and stumps from sir i got it and now i forgot it again :P so thanks agaiinn! :P
  11. daredevil

    i guesss u can say the same for me waisay bcz i m not studying -__- it sucks :/

    i guesss u can say the same for me waisay bcz i m not studying -__- it sucks :/
  12. daredevil

    :P

    :P
  13. daredevil

    yh i answered that... hope u get it now :) (y)

    yh i answered that... hope u get it now :) (y)
  14. daredevil

    not aWWsUUMM!! :P but okay :P just waiting for it to be done with..... how abt urs?

    not aWWsUUMM!! :P but okay :P just waiting for it to be done with..... how abt urs?
  15. daredevil

    Chemistry: Post your doubts here!

    no no on the left side it has O and on the right it has H in B part. in C it has O on one side and Cl on the other side. that is what i meant by OPPOSITE poles. thus dipoles are formed. in B of q10 the activation energy is really high so the reactoin will take a long time to proceed bcz it...
  16. daredevil

    Chemistry: Post your doubts here!

    B is ur answer bcz in A and D there are no poles bcz similar elements on both sides of the compound cancel the polarity of the compound. with those options eliminated, C has O and Cl at the two oppoite sides while B has Cl and H. the greater difference of electronegativity or polraity is between...
  17. daredevil

    Chemistry: Post your doubts here!

    didn't understand it o.O
  18. daredevil

    Chemistry: Post your doubts here!

    oo my no ...thts a tough one -__- :/
  19. daredevil

    Chemistry: Post your doubts here!

    oo my no ...thts a tough one -__- :/
  20. daredevil

    Chemistry: Post your doubts here!

    the stronger the reagents, the more the enthalpy change. for P the acid should be weaker than HCl and so it is ethanoic acid. R should be stronger than Q so ammonia is Q and KOH is R. i hope u get it. if u don't then reply and i'll c if i can explain further. (y)
Top