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  1. U

    Physics: Post your doubts here!

    22. option A. intensity = constant * (amplitude^2) intensity is directly proportional to the square of amplitude. 10^12 = a^2 a = square root of 10^12 a = 10^6
  2. U

    Beautiful Articles

    both of the articles are superb... hope ALLAH guides us all to the straight path AMEEN
  3. U

    Chemistry: Post your doubts here!

    [(0.2 + x)^2] / [(0.5 - x)^2] = 1.44 (0.2 + x) / (0.5 - x) = 1.2 0.2 + x = 0.6 - 1.2x 2.2x = 0.4 x = 0.18 CO2 AND H2 = 0.5 - 0.18 CO AND H2O = 0.2 + 0.18
  4. U

    Mathematics: Post your doubts here!

    i) stationary point is where the derivative is zero. dy/dx = 12x - 3x^2 = 0 x (12 - 3x) = 0 x = 0 12 - 3x = 0 x = 0 x = 4 y = 6x^2 - x^3 at x = 0, y = 0 at x = 4, y = 32 coordinates are (0,0) and (4,32) nature is determined by double derivative. d^2y / dx^2...
  5. U

    Suit me a career please!

    is there any scope of petroleum engineering in pakistan?
  6. U

    Mathematics: Post your doubts here!

    yar how can u say that we will use ln? cant we use lg? :%)
  7. U

    Grades!

    in AS its 90% in A2 its 80%
  8. U

    I can't decide to take Stat1 or mech2 in my A2 maths

    u shud take S1 especially if u r a private student cox very few teachers teach M2 in private institutions ...
  9. U

    Chemistry: Post your doubts here!

    at a higher temp the curve should be towards right and smaller than the first curve. this is true only in option B and D. but B is the correct ans because the area under the curve should remain same at both the temp which is nt true for option D
  10. U

    Mathematics: Post your doubts here!

    ur welcummmm :) han i really love maths :)
  11. U

    Mathematics: Post your doubts here!

    6ii) stationery value is when derivative is zero... dz/dx = 3(1) + (-1) 1200 * x^-2 = 3 - (1200/x^2) for stationery value of x: 3 - (1200/x^2) = 0 3 = 1200/x^2 400 = x^2 x = 20 for stationery value of z input the value of x in the original equation = 3(20) + (1200/20)...
  12. U

    Mathematics: Post your doubts here!

    5i) tan = sin/cos cos^2 = 1- sin^2 2[sin^2/cos^2] * sin^2 = 1 (2 sin^4)/cos^2 = 1 2 sin^4 = cos^2 2 sin^4 = 1 - sin^2 2sin^4 + sin^2 -1 =0
  13. U

    Physics: Post your doubts here!

    Re: Paper 1 Doubts !! nov 06 21) pressure = density*g*h 17.5 * 10^6 = (830*9.8*x) + (1000*9.8*(2000-x)) x= 1260 ~= 1270
  14. U

    Physics: Post your doubts here!

    Re: Paper 1 Doubts !! june 06 33) 500:1000 = 1:2 2000:1000 = 2:1 500 ohms resistor will consume 4 V. at X there will be a potential of 4V 2000 ohms resistor will consume 8 V. at Y there will be a potential of 8 V so the difference of p.d between X and Y is 8-4 = 4 V 36) all the resistors have...
  15. U

    Physics: Post your doubts here!

    c) energy = work done total energy = work done by both the springs extension 1 = 4.5 - 1.5 = 3 cm extension 2 = 4.5 + 1.5 = 6 cm energy = 1/2 * k(x2^2 - x1^2) + 1/2 * k(x2^2 - x1^2) 1/2 * 1600 (0.06^2 - 0.045^2) + 1/2 * 1600 (0.03^2 - 0.045^2) 1.26 + (-0.9) 0.36 J 0.36 = 1/2 * m * v^2 (0.36 *...
  16. U

    Physics: Post your doubts here!

    a) the loading and unloading graph overlaps each other showing no permanent deformation so the change is elastic. b) w= area under graph f=kx area of trapezium = 1/2 [(x2 - x1) (f1 + f2)] 1/2 [ (x2 - x1) (kx1 + kx2)] 1/2 * k { x2^2 - x1^2}
  17. U

    Physics: Post your doubts here!

    Re: Paper 1 Doubts !! june 06: ans 9= max velocity is at mean position and zero at max height. so the distance - time graph will be as shown in the attachment. the points A,B,C,D will be as shown. so the velocity at lowest point of motion is at D
  18. U

    Physics: Post your doubts here!

    charge = current * time charge = 10 * 1 = 10 coulumbs total charge passing through the wire is 10 C charge of electrons is 1.6 * 10^-19 number of electrons = total charge / electron charge = 10 / (1.6 * 10^-19) = 6.25 *...
  19. U

    Physics: Post your doubts here!

    7aii) 1) electric field strength = force/charge E=F/q F=Eq 2) for horizontal motion; s=vt L=vt L/v=t bii) momentum change = force*time = (Eq)*(L/v) = (EqL)/v
  20. U

    Physics: Post your doubts here!

    the time is increased, not the speed. so the distance increase with time cii) s = (1/2) * a * (t^2) s/(t^2)= (1/2) * a s/(t^2) = gradient twice of gradient = acceleration
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