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can someone please upload a solution for Q5.
for part (I) I got 10.5v^2
part (II) 135 x J or something
part (III) I calculated the tension and the work done by the tension and thn used the formula
work done by tension = ke gain - PE loss + work done against resistance, to calcuclate the work done against resistance
for part (I) I got 10.5v^2
part (II) 135 x J or something
part (III) I calculated the tension and the work done by the tension and thn used the formula
work done by tension = ke gain - PE loss + work done against resistance, to calcuclate the work done against resistance