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A level Statistics doubt??Post your doubts here!

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could u plzz jst explain me a bit more in detail i m confused a bit ... if u dont mind
The times taken to play Beethoven’s Sixth Symphony can be assumed to have a normal distribution
with mean 41.1 minutes and standard deviation 3.4 minutes. Three occasions on which this symphony
is played are chosen at random.
(i) Find the probability that the symphony takes longer than 42 minutes to play on exactly 1 of these
occasions.
no need to take .5 into account since no use of binomial here
However
Ana meets her friends once every day. For each day the probability that she is early is 0.05 and the
probability that she is late is 0.75. Otherwise she is on time.
(i) Find the probability that she is on time on fewer than 20 of the next 96 days
in this question need find mean/sd with binomial formula mean(96*0.2) and sd=root(96*.2.8)
so x is <19.5
 
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plz someone do this question
i did this but i want to ask something :)

The random variable X is normally distributed. The mean is twice the standard deviation. It is
given that P(X > 5.2) = 0.9. Find the standard deviation.
 
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and also some one plz explain this
it will be so nice :)

A normal distribution has mean µ and standard deviation σ. If 800 observations are taken from
this distribution, how many would you expect to be between µ −σ and µ +σ?
 
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i
plz someone do this question
i did this but i want to ask something :)

The random variable X is normally distributed. The mean is twice the standard deviation. It is
given that P(X > 5.2) = 0.9. Find the standard deviation.
i did this and got s.d as 1.58
 
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i
i did this and got s.d as 1.58
i got 0.828 but correct answer is 7.24. In mark scheme they are getting -1.281 but i m getting it 1.281. I just want to know that y we have to consider negative sign here
 
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and when we assume unknnown value normal distriution chap how we geet to knw that value is postiv or neg/?
e.g let p(Z>a) = 0.25 and t is positive, hw do we knw that?anyone plzz
 
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