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All the best man ! May Allah be with you ! And all of us !!Hey guys good luck.for stats today..I hope we all can tackle it easily n get good marks...all the best
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All the best man ! May Allah be with you ! And all of us !!Hey guys good luck.for stats today..I hope we all can tackle it easily n get good marks...all the best
check thisi tried it that way, doesnt match, the examiners report says to use 0.97 as the probability :S
i am sorry , just saw ur post.. ok if for example 2<x<7 then class boundry is 1.5<x<7.5... just simply sub 0.5 from lower one and add 0.5 to upper one .. got it?kiara15 ASTAR syed1995 or any 1....
Help me knw how to know the lower class boundary from a cumulative frequency table ....
for example one in Qp 6 in here:
http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s11_qp_61.pdf
i dnt understand 6 iv as in the ms! pls help!!! Reply asap!
Draw a sum table... if u cant lemme knw nowi need help in http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s12_qp_63.pdf
I'm stuck in Q4(ii)
A staranyone plz help me in Q1 (ii) Anika Raisa kiara15 syed1995 or any one
http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20(9709)/9709_w09_qp_62.pdf
Yeah plz tell me..Draw a sum table... if u cant lemme knw now
Okay i've done table.. Count the no of 2s, 3s 4s 5s n 6 s.. make a probability distribution table with thatYeah plz tell me..
Ameen . but thing s dont look so good the paper i am doing made me dizzyGood Luck for the paper everyone..! May Allah make us all get As and A*s in our papers
Ameen . but thing s dont look so good the paper i am doing made me dizzy
dnt solve papers nw, jus go thru yr book... Inshallah u'll do gr8... n see the nov 2011 wala cu frequency qs the last partAmeen . but thing s dont look so good the paper i am doing made me dizzy
Theres no clue .. I mean its part of the working. You dont HAVE to do any extra working to get .97, it jut comes. If you know what i mean.I have the same doubt but i dont understand why do we have to do this step to get 0.97 ? Like what is clue for me to do this step?
For a normal distribution, 75% data lies below the upper quartile, 75% lies above the lower quartile and 50% lies in the interquartile range. Use any one of the resulting eqs and ull get the answeranyone plz help me in Q1 (ii) Anika Raisa kiara15 syed1995 or any one
http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20(9709)/9709_w09_qp_62.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w09_qp_62.pdf hell every single question except last three and second i coudnt do parts
thanks sis, thats informativeFor a normal distribution, 75% data lies below the upper quartile, 75% lies above the upper quartile and 50% lies in the interquartile range. Use any one of the resulting eqs and ull get the answer
P(X<63)= 0.75
P(X>39)= 0.75
P(39<X<63)= .5
ahh yes i have to review all formulaes i dont know y stats makes me feel after i found out the answer that y didnt i write it it was sooo easy :/For a normal distribution, 75% data lies below the upper quartile, 75% lies above the upper quartile and 50% lies in the interquartile range. Use any one of the resulting eqs and ull get the answer
P(X<63)= 0.75
P(X>39)= 0.75
P(39<X<63)= .5
i have to thank Alice123 for it or i wouldhave beeen dead if i hadent reviewed itAh yes this one was a real *****.
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