- Messages
- 17
- Reaction score
- 16
- Points
- 3
For the first two, yes, except youll write L1-L2 in the denominator for case 2. For the other 2, error is {0.1/L1+ 0.1/L2} multiplied by their product or quotient
Hope this helps
So for example if
L1 = 2
L2 = 3
For them being multiplied I will do
( 0.1/2 + 0.1/3 )* L1*L2
(* shows multiplied by)
and for divided
( 0.1/2 + 0.1/3 )* L1/L2
and for L1^4 (^ is raised to power)
(0.1/2)*4