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AS Physics P1 MCQs Preparation Thread.

Thought blocker

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Hanona said:
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w09_qp_11.pdf
Click to expand...
14)
The horizontal velocity will remain the same.
The vertical velocity will be zero at that time.
So the kinetic energy will be due to horizontal velocity alone which is v*cos*45 = v √2/2
Kinetic energy at max point = 1/2 * m * (v √2/2)² = [1/2 m v² ]* 1/2 (the thing in square brackets is equal to kinetic energy at the beginning) so k(max)=0.5K(initial)
Got it :) ?
 
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q 3 -- at the maximum height the horizontal component is 0 and the only component acting is the vertical one which when you resolve gives you vsin(x) (this is the final velocity) now considering the equation v^2=u^2+2gs you substitute and rearrange ...
q -5 you add up all the PERCENTAGE uncertainities so 4 pie is a constant , l has 4% and T has 1% but remember there is a square here so now it is 2 x 1% = 2% now you add them up to get 6 %
q 8 - by the time it takes over the goods train they should have travelled the same distace so s1=s2 ..... 10t = 1/2 x 1/2 x t^2 ... solve and youll get 40 s
q-21----total pressure at base = pressure of water and oil.... 17.5 x 10 ^ 6 = 9.81 x (x) x 830 + 9.81 x 1000 x (2000-x ) solve it and youll get D as the answer,,,,
 
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ziremm

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Hanona said:
q 3 -- at the maximum height the horizontal component is 0 and the only component acting is the vertical one which when you resolve gives you vsin(x) (this is the final velocity) now considering the equation v^2=u^2+2gs you substitute and rearrange ...
q -5 you add up all the PERCENTAGE uncertainities so 4 pie is a constant , l has 4% and T has 1% but remember there is a square here so now it is 2 x 1% = 2% now you add them up to get 6 %
q 8 - by the time it takes over the goods train they should have travelled the same distace so s1=s2 ..... 10t = 1/2 x 1/2 x t^2 ... solve and youll get 40 s
q-21----total pressure at base = pressure of water and oil.... 17.5 x 10 ^ 6 = 9.81 x (x) x 830 + 9.81 x 1000 x (2000-x ) solve it and youll get D as the answer,,,,
Click to expand...
thank you very much (y):):):)
 
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ashoo123 said:
Hey could someone pls help with these questions... q 9, 15, 17 winter 2009 http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w09_qp_11.pdf

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w09_ms_11.pdf

thnkx in advance!
Click to expand...

q15
total momentum is zero.
momentum of 2kg trolley is 2*2=4
so 1*(-4)=-4 resultant momentum will be zero
4+(-4)=0
Kinetic eng of 2kg: 1/2 * 2* 2^2 = 4J
KE of 1kg= 1/2*1*4^2= 8J
8+4=12 J
 
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ashoo123 said:
Hey could someone pls help with these questions... q 9, 15, 17 winter 2009 http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w09_qp_11.pdf

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w09_ms_11.pdf

thnkx in advance!
Click to expand...
9)
Here Pi = Pf
Pi = 2mu - mu = mu
now check in all optons, and see where does Pi = Pf
A C D has Pi =Pf now we are asked for Elastic collision, so A

17)
Theory based answer. Read the chapter - Matters.
 
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ziremm said:
q15
total momentum is zero.
momentum of 2kg trolley is 2*2=4
so 1*(-4)=-4 resultant momentum will be zero
4+(-4)=0
Kinetic eng of 2kg: 1/2 * 2* 2^2 = 4J
KE of 1kg= 1/2*1*4^2= 8J
8+4=12 J
Click to expand...
Ohh! thanks for tht ;) .. I was trying the resultant momentum equals zero thing but i messed up the symbols...thts y i couldnt come up with a reasonable ans :p:p
 
ashoo123

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Thought blocker said:
9)
Here Pi = Pf
Pi = 2mu - mu = mu
now check in all optons, and see where does Pi = Pf
A C D has Pi =Pf now we are asked for Elastic collision, so A

17)
Theory based answer. Read the chapter - Matters.
Click to expand...

Umm... I did the Pi=Pf nd was confused between A and C...now momentum nd collisions isnt really my best area but in an elastic collision cant both objects move in the same direction? :p
 
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