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AS Physics P1 MCQs Preparation Thread.

umarashraf

umarashraf

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lavanyamane said:
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s10_qp_12.pdf
Q.4, 15, 27, 28, 34 please? :)
Click to expand...

34.. .. make it a numerical my assuming each resistor to be of 2 ohms and battery to supply emf of 6V... now total effective resistance will be 3 ohms... total current will now be p=IV 12=i6 i=2A... now look the diagram again, P will have 2A current while Q R will have 1A each... now by applyin P=I^2 R... P=1^2 * (2) you will have @ as answer... i didnt have any shorter way to solve this one...
 
umarashraf

umarashraf

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umarashraf

umarashraf

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lavanyamane said:
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s10_qp_12.pdf
Q.4, 15, 27, 28, 34 please? :)
Click to expand...

27.. electric field is away from the observer and into the page.. elecrtic field is always from positive to ngative... this means that the observer is facing positive plate directly... electrons would be repelled by the negative plate and will move towards the positive plate... behind where the observer is standing... i think...:)
 
USMAN Sheikh

USMAN Sheikh

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leosco1995 said:
Q15)

At terminal velocity, weight = air resistance
so mg = kv

And v = mg/k

Now substitute v with mg/k in 1/2 mv^2 formula to get the answer.

Q22) You want high sensitivity for small masses, i.e. a big change in extension for smaller masses. This means a lower value of 'k' is needed for the smaller masses. The rigid box is there to prevent external forces like wind from pushing the masses on the spring. Also, when you have larger masses on the spring, then you need a higher value of 'k', i.e. a small extension for a large load. So the answer would be A.

Q32)

A and B are wrong because the e.m.f. can't decrease, its the energy being provided by the battery.

Also, VT = E - Ir (terminal voltage i.e. voltage across the battery is equal to e.m.f. - internal resistance * current).

From this equation, we can confirm that answer C is correct.

S11/12

Q16) Assume the length of the rod to be 1m. You know that the weight lies exactly in the middle, so each side is 0.5m apart. If you take the wall to be the pivot, then you can form an equation,

F sin 30 * 1 = 0.5 * 10
F = 10.0 N

Q19)

Work = force * distance in direction of force
10 = 0.005 * force
force = 2000 N

Q34) The answer to this one is a fact, you have to learn it. The e.m.f. depends on both r and R.

A is wrong because using the equation VT = E - Ir, the terminal voltage will change.
B is wrong because the current would decrease, not increase.
C is wrong because the e.m.f. of the battery can't change.
D is a correct statement. You can verify this yourself using P = I^2 * R
Click to expand...
thanks alot but there are few aswell pls resolve them too tey are on page 38

lesco thanks alot man :) u r doing a great job few more questions for u :) kindly solve them pls :)
q 14 and 36 of june 11 variant 11
q 26 28 36 of november 11 variant 11 :)
here u go pls for papers link kindly go on page 38 pls man help me leosco1995
 
USMAN Sheikh

USMAN Sheikh

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umarashraf said:
27.. electric field is away from the observer and into the page.. elecrtic field is always from positive to ngative... this means that the observer is facing positive plate directly... electrons would be repelled by the negative plate and will move towards the positive plate... behind where the observer is standing... i think...:)
Click to expand...
buddy kindly resolve my doubts on page 38 pls :(


lesco thanks alot man :) u r doing a great job few more questions for u :) kindly solve them pls :)
q 14 and 36 of june 11 variant 11
q 26 28 36 of november 11 variant 11 :)
here u go links are on page 38 pls mate :(
 
applepie1996

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omg

omg

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knightrider1994 said:
Oh yes. My bad ! Can you explain the other questions as well ?
Click to expand...
for q.16, kinetic energy before the collision = 1/2mv^2 + 1/2mv^2 => mv^2
after collision as masses stick, so mass will b added (2m) and the speed will b halvd as momentum will b conserved.
so, k.e after the collision = 1/2(2m)(v/2)^2
=1/2mv^2!
 
bloody_mary

bloody_mary

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umarashraf said:
17.. efficiency=output/input * 100 if input is 100 output is 8... so 8/100 * 100 =8...

31... electron would be attracted by the positive charge, so B and D are fundamentally wrong... now since the electron is moving against the electric field, it will be deflected out of the field by the negative charge... line of field represents the direction of the field ...
Click to expand...

thanks :D
but for 31 why can't the answer be C?
 
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