AS Physics P1 MCQs Preparation Thread.

[sweetjinnah]

In M/J 2004 #25 ,why is point P moving downwards?

in this u need to make a new wave nd u will see that point P moves downwards cz the direction of wave is to the right....nd Q barely moves hence the answer is A ..hope u got it...

 

[sweetjinnah]

even i downloade this one but somehow it is for some other paper :S

chek out thishttp://www.freeexampapers.com/#A Level/Physics/CIE

 

[salvatore]

Pressure=Density*G*depth

the more the depth the more the pressure.. pressure at same depths is constant. So answer should be A.

Thanks mate

 

[Lyfroker]

chek out thishttp://www.freeexampapers.com/#A Level/Physics/CIE

i did, they have different question papers :S

 

[sweetjinnah]

i did, they have different question papers :S

u wanted P1 of May june 2001 ryt??

 

[Lyfroker]

u wanted P1 of May june 2001 ryt??

i hv a booklet fo ppr and need the ms, but they have diff ppr n ms on that site

 

[leosco1995]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s09_qp_1.pdf
Could anyone please explain no. 11?
I don't understand why P is less than R.. since the body is underwater, isn't P supposed to be greater than R??

What exactly makes you think that?

The pressure will be greater at the greater depth. Force = Pressure * Area so the force is going to be greater at the bottom too. The fluid at the top is going to push down on the particles at the bottom due to gravity so there's more pressure at the bottom.

 

[leosco1995]

I recommend people check out http://www.xtremepapers.com/community/threads/as-physics-p1-mcqs-yearly-only.17330/ and see if there answer is well-explained there before posting their doubts here BTW.

 

[Raghad Dia]

in this u need to make a new wave nd u will see that point P moves downwards cz the direction of wave is to the right....nd Q barely moves hence the answer is A ..hope u got it...

Thank you very much!

 

[Raghad Dia]

#9 & #26 M/J 2004 please

 

[salvatore]

#9 & #26 M/J 2004 please

(9) Ethanoic acid is a weak acid so it wont ionise completely. Sodium hydroxide is an alkali so it doesn't produce H+. Sulphuric acid has 2 H+.
So answer is B. Nitric acid is a strong acid and produces one H+

(26) As you can see, there are two intermediates formed in the process. Hence, the energy diagram will have two humps, one for each intermediate.
The second hump should always be lower because the reaction can only proceed as long as the energy barrier for the following step is less then the preceding one.
So the correct answer is D

Hope that helped

 

[Raghad Dia]

Th

(9) Ethanoic acid is a weak acid so it wont ionise completely. Sodium hydroxide is an alkali so it doesn't produce H+. Sulphuric acid has 2 H+.
So answer is B. Nitric acid is a strong acid and produces one H+

(26) As you can see, there are two intermediates formed in the process. Hence, the energy diagram will have two humps, one for each intermediate.
The second hump should always be lower because the reaction can only proceed as long as the energy barrier for the following step is less then the preceding one.
So the correct answer is D

Hope that helped

This is chemistry not physics x_x thanks anyways i got help

 

[salvatore]

Th
This is chemistry not physics x_x thanks anyways i got help

Omg.. I thought I was in the chemistry thread!!

Anyways, it helped me revise a bit of chemistry

 

[ahmed abdulla]

Omg.. I thought I was in the chemistry thread!!

Anyways, it helped me revise a bit of chemistry

 

[syed1995]

I is directly propotional to a^2
I=ka^2
I=k*(2a)^2
I=4ka^2
I=4 times the previous Io


I is directly propotional to f^2

Frequency is halved since the time period is doubled..

so
I=kf^2
I=k(1/2a)^2
I=1/4kf^2
I=one fourth of the previous Io

so.. we will multiply both the coefficents of k to get the final value.

1/4 * 4 = 1
I=ka^2

therefore I remains same.

 

[leosco1995]

It's just math. They said the intensity is proportional to the square of the amplitude as well as square of the frequency

P = Io.

Q has double the amplitude, so 4x the intensity = 4Io.
Q has half the frequency,so 1/4x the intensity = 4Io * 1/4 = Io.

 

[ahmed abdulla]

I is directly propotional to a^2
I=ka^2
I=k*(2a)^2
I=4ka^2
I=4 times the previous Io


I is directly propotional to f^2

Frequency is halved since the time period is doubled..

so
I=kf^2
I=k(1/2a)^2
I=1/4kf^2
I=one fourth of the previous Io

so.. we will multiply both the coefficents of k to get the final value.

1/4 * 4 = 1
I=ka^2

therefore I remains same.

thanks ... one question...
When the strain in the specimen is increased, what happens to the resistance of the wire?
as the ansers .. > It increases, because the length increases and the cross-sectional area decreases. ...but how ..? strain is inversly proportional to length

 

[syed1995]

thanks ... one question...
When the strain in the specimen is increased, what happens to the resistance of the wire?
as the ansers .. > It increases, because the length increases and the cross-sectional area decreases. ...but how ..? strain is inversly proportional to length

Can you link the paper.

 

[ahmed abdulla]

Can you link the paper.

its no. 33 http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_w05_qp_1.pdf
btw tell me about 34 too

 

[beeloooo]

Hey can anyone help me with mcq no : 6 ? its really important i fail to understand such things :/