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Biology; Chemistry; Physics: Post your doubts here!

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It takes 45 cm^3 of H3PO4 to neutralize 25 cm^3 of 1.8 mol/dm^3 of KOH. What's the concentration of H3PO4? I know how to do it but the answer i was getting wasn't matching the ms... (can't post it here because it was an old past paper)
 
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It takes 45 cm^3 of H3PO4 to neutralize 25 cm^3 of 1.8 mol/dm^3 of KOH. What's the concentration of H3PO4? I know how to do it but the answer i was getting wasn't matching the ms... (can't post it here because it was an old past paper)
Which past paper ..?
 
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It takes 45 cm^3 of H3PO4 to neutralize 25 cm^3 of 1.8 mol/dm^3 of KOH. What's the concentration of H3PO4? I know how to do it but the answer i was getting wasn't matching the ms... (can't post it here because it was an old past paper)

What is the answer in the marking scheme?
 
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It takes 45 cm^3 of H3PO4 to neutralize 25 cm^3 of 1.8 mol/dm^3 of KOH. What's the concentration of H3PO4? I know how to do it but the answer i was getting wasn't matching the ms... (can't post it here because it was an old past paper)
First get the number of moles of KOH by doing this:
1.8 x 25/1000
then construct an equation and balance it and then use the ration method to find the moles of the H3PO4: H3PO4 + 3KOH = K3PO4 + 3H2O
no. of moles = Molarity x volume in dm^3
 
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It takes 45 cm^3 of H3PO4 to neutralize 25 cm^3 of 1.8 mol/dm^3 of KOH. What's the concentration of H3PO4? I know how to do it but the answer i was getting wasn't matching the ms... (can't post it here because it was an old past paper)
The answer that came out when i calculated is 0.33 mol/dm3

First find the number of moles of KOH that comes out as 0.045 moles
According to the equation 1 mol of H3PO4 reacts with 3 moles of KOH so by the ratio method there are 0.015 moles of H3PO4 in 45cm3.
As there are 0.015 moles in 45cm3 so there will 0.33 moles in 1000 cm3 that is the concentration of the acid: 0.33mol/dm3
 
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0.3 (and i am getting 0.3333333333) and they said in the instructions that all numerical answers should be to 2 d.p.) =/
That is the correct answer, if you write 0.33 it wouldnt matter because 0.3 has been obtained by rounding off 0.33 according to me :p
 
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The answer that came out when i calculated is 0.33 mol/dm3

First find the number of moles of KOH that comes out as 0.045 moles
According to the equation 1 mol of H3PO4 reacts with 3 moles of KOH so by the ratio method there are 0.015 moles of H3PO4 in 45cm3.
As there are 0.015 moles in 45cm3 so there will 0.33 moles in 1000 cm3 that is the concentration of the acid: 0.33mol/dm3
When u divide 0.015/0.045.thn u get 0.33333333333but the answer in mark scheme is only 0.3 !
 
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Hmmm... well i guess that would be an error then =/
Ok here's another one:

You have 3 types of coal. All three of them have sulphur in different amounts which burn to produce SO2. This gas reacts with KMnO4 and turns it's colour from purple to colorless. Which one has the most sulphur in it? 6 mark question so you have to mention all the apparatus and all. I got 4 because of lack of time (and a teacher who seemed to have a phadda with her husband or something) although i still don't get what i missed :p So, help required. Thanks :D
 
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Hmmm... well i guess that would be an error then =/
Ok here's another one:

You have 3 types of coal. All three of them have sulphur in different amounts which burn to produce SO2. This gas reacts with KMnO4 and turns it's colour from purple to colorless. Which one has the most sulphur in it? 6 mark question so you have to mention all the apparatus and all. I got 4 because of lack of time (and a teacher who seemed to have a phadda with her husband or something) although i still don't get what i missed :p So, help required. Thanks :D
I see, this focuses on reducing agent, the higher the percentage of SO2 the quicker KMnO4 would be decolourize.
 
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