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but i supose all v have to worry about (4 o levels is) the molten part is very easy positive ions go towards the cathose n negativ towards anodeYes and ammonium carbonate.
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but i supose all v have to worry about (4 o levels is) the molten part is very easy positive ions go towards the cathose n negativ towards anodeYes and ammonium carbonate.
You nailed it!but i supose all v have to worry about (4 o levels is) the molten part is very easy positive ions go towards the cathose n negativ towards anodeas fr aqueous, its oxygen everytym xcpt fr when it is chlorine, bromine or iodine in CONCENTRATED form...as for cathode, if the positive ions are above hydrogen in reactivity series thn hydrogen is discharged n if below hydrogen (copper n silver) thn the metal is discharged. m i write ? :-/ please correct me if im wrong
7oh. n theres another dumb question. N this seriously has started pissing me off! GOD iv got no tym left n im cuming up wid such problems. aniways, ur valuable help is needed here.
http://papers.xtremepapers.com/CIE/Cambridge International O Level/Chemistry (5070)/5070_s06_qp_4.pdf question 7 & 9(a)
For 7, it's (d) Redox, since the zinc replaces the copper (II) sulphate (since it is more reactive) and reduces it whereas the zinc itself gets oxidized and hence a redox reaction.oh. n theres another dumb question. N this seriously has started pissing me off! GOD iv got no tym left n im cuming up wid such problems. aniways, ur valuable help is needed here.
http://papers.xtremepapers.com/CIE/Cambridge International O Level/Chemistry (5070)/5070_s06_qp_4.pdf question 7 & 9(a)
Knowing about carbonates is not part of the syllabus but..well i dunno abt it i jxt wanted to knw abt carbonates
i was finding 'displacement reaction' in the options. i get the point tht y is it redox. so should i consider it a rule tht displacement reactions are redox reactions? does this apply everywhere?For 7, it's (d) Redox, since the zinc replaces the copper (II) sulphate (since it is more reactive) and reduces it whereas the zinc itself gets oxidized and hence a redox reaction.
For 9, well iron (III) is the highest oxidation that an iron element can reach so potassium manganate (VII) cannot further oxidize it and hence won't react with it.
Hope that helps![]()
hmmmm thnx i got itKnowing about carbonates is not part of the syllabus but..
SO4 2-
NO3 -
CO3 2-
OH-
Cl -
Br -
I -
Here is the list.
Iodide ions are most readily discharged whereas sulphate and nitrate are not easily discharged.
Besides, in any event if nitrate, sulphate or carbonate is present then hydroxide (oxygen gas) will be discharged at anode.
Hope you get it![]()
Yes you can say that displacement reactions are redox since one element is oxidized and the other is reduced. No extra ions are formed. No problemi was finding 'displacement reaction' in the options. i get the point tht y is it redox. so should i consider it a rule tht displacement reactions are redox reactions? does this apply everywhere?
aaaaaaaa.......okay i get it...the prblem is,,,u cn never learn to answr such questions. i did have all the knowledge required in this question yet was cluless....It helpd alot! thankyouuuuu!!
hmmmm thnx i got it![]()
basically the reasoning for this is to complicated for O and even As level purposes basically you need to know that sulphate ions are higher in reactivity series so will never be discharged. to make sulphate/nitrates/carbonates ions discharge you also need to break up the anion which is not a feasable process.(OH-) ion is a exceptionthnx both ov u and what abt nitrates???
hmm thnxbasically the reasoning for this is to complicated for O and even As level purposes basically you need to know that sulphate ions are higher in reactivity series so will never be discharged. to make sulphate/nitrates/carbonates ions discharge you also need to break up the anion which is not a feasable process.(OH-) ion is a exception
moles=given mass/mr. so mr of hcl is 1+35.5=36.5. so 36.5*1.43=52.195. i hope dis helps. can u check the answr in marking scheme so I can be sure if my method is right or notif HCl has concentration of 1.43mol/dm^3
what is its concentration in g/dm^3??????
plz also tell formula![]()
Your method is correct. And that should be the correct answer as well.moles=given mass/mr. so mr of hcl is 1+35.5=36.5. so 36.5*1.43=52.195. i hope dis helps. can u check the answr in marking scheme so I can be sure if my method is right or not
Just like TheStallion-Reborn stated, since both the concentrations are in dm^3, you simply have to calculate the mass(g) of 1.43 moles of HCL using the formula (Mass = No. of moles * Mr/Ar) so this would simply get the concentration in g/dm^3.if HCl has concentration of 1.43mol/dm^3
what is its concentration in g/dm^3??????
plz also tell formula![]()
moles=given mass/mr. so mr of hcl is 1+35.5=36.5. so 36.5*1.43=52.195. i hope dis helps. can u check the answr in marking scheme so I can be sure if my method is right or not
thnx guys,but stallion reborn,this question isnt from past papers but I think you are rightYour method is correct. And that should be the correct answer as well.
Just like TheStallion-Reborn stated, since both the concentrations are in dm^3, you simply have to calculate the mass(g) of 1.43 moles of HCL using the formula (Mass = No. of moles * Mr/Ar) so this would simply get the concentration in g/dm^3.
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