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well for Q7b(ii) well u might have got potiential difference as 195volts we have current=65amps as we know charge=current *time. in this case time is 1second so we will multiply it with 65 and get 65 coulombs we know that potiential difference equals workdone divided by charges flowing in the circuit. lets rearrange this equation and we will get workdone equals potiential difference*charges and we will get 195*65=12675 joulesAlso,can anyone help me out in phy? Papers:
5040_w11_qp22 Q7b(ii)
5040_w11_qp21 Q9b(v)
sorry i cudnt upload the papers..