weren't the initial volumes same for D as well, and then a shift towards end diastole?no the curve showed the stroke nd end diastolic pressure to b 200. both. so cant b C
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weren't the initial volumes same for D as well, and then a shift towards end diastole?no the curve showed the stroke nd end diastolic pressure to b 200. both. so cant b C
nope curve didnt start from originweren't the initial volumes same for D as well, and then a shift towards end diastole?
I know that, but the point where it started from, the coordinates of that starting point, weren't they equal?nope curve didnt start from origin
there werent any othr reading so we cant assume dat... nd no othr optn was correct so DI know that, but the point where it started from, the coordinates of that starting point, weren't they equal?
Hmmmm, it was probably D then.there werent any othr reading so we cant assume dat... nd no othr optn was correct so D
yeah. wat did u do of the tRNA questn? otherwise ur ans match mine but i did the large animal ans 1 nd 2...Hmmmm, it was probably D then.
http://en.wikipedia.org/wiki/Frank–Starling_law_of_the_heart the graph was like this ?u r welcum but ans was D
yeah. wat did u do of the tRNA questn? otherwise ur ans match mine but i did the large animal ans 1 nd 2...
yeah the cardiac output graph. started frm the point where derez the big dothttp://en.wikipedia.org/wiki/Frank–Starling_law_of_the_heart the graph was like this ?
it wasnt comparing large nd small animals. it was comparing organisms wid nd widout transport systemView attachment 13167
indeed you are correct! Thanks for correcting me...
For tRNA question i selected the option in which statements 1 and 2 were correct and statement 3 was incorrect. For large animals 1 was obviously correct and 3 (related to SA to volume ratio) was clearly incorrect. Statement 2 was also incorrect, since the rate of gas exchange depends on activity and some large animals are less active than small animals.
did the same of tRNAView attachment 13167
indeed you are correct! Thanks for correcting me...
For tRNA question i selected the option in which statements 1 and 2 were correct and statement 3 was incorrect. For large animals 1 was obviously correct and 3 (related to SA to volume ratio) was clearly incorrect. Statement 2 was also incorrect, since the rate of gas exchange depends on activity and some large animals are less active than small animals.
But it asked about large animals, did it not? So one must understand that not all large animals have high rate of gaseous exchange (those that are less active), so statement 2 did not apply to all large animals, whereas statement 1 did! Therefore, only statement 1 was correct.it wasnt comparing large nd small animals. it was comparing organisms wid nd widout transport system
no i think it asked dat y do sme organisms need transport system nd sme dnt? didnt it?But it asked about large animals, did it not? So one must understand that not all large animals have high rate of gaseous exchange (those that are less active), so statement 2 did not apply to all large animals, whereas statement 1 did! Therefore, only statement 1 was correct.
no, it asked why large animals need them. Specifically mentioned large animals.no i think it asked dat y do sme organisms need transport system nd sme dnt? didnt it?
hmmmmm... i thut the large animals was just in the statement. will confirm it tomorrow by getting my question paperno, it asked why large animals need them. Specifically mentioned large animals.
that implies that diffusion rate will b faster (due to large surface area) and so no transprt sysytem is neededFor tRNA 1 and 2 was correct. i got that wrong and why shouldnt it be a large surface area to volume ratio? Wouldnt that imply that there are more cells to transport stuff to and from? i know that under normal circumstances this increases diffusion rate but in an animal with a large surface area to volume ratio, it should mean that there are lots of cells so diffusion should be slower :S at least this is what i thought but clearly i'm wrong
large surface area to volume ratio means that the surface area is greater and volume is less, so cells requiring substances are not far from the site of absorption or production of those substances, hence no efficicent transport system may be required. It is the small surface area to volume ratio due to which a transport system is required. In the question a large surface area to volume ratio was given as statement 3, which was incorrect.For tRNA 1 and 2 was correct. i got that wrong and why shouldnt it be a large surface area to volume ratio? Wouldnt that imply that there are more cells to transport stuff to and from? i know that under normal circumstances this increases diffusion rate but in an animal with a large surface area to volume ratio, it should mean that there are lots of cells so diffusion should be slower :S at least this is what i thought but clearly i'm wrong
dude how can u say D, in d when the volume of blood in ventricals was less then the blood pumped out by the ventricals at 50cm^3....thats impossible, so where does that blood come from........i clearly ignored thatans was D
ur rite it is CBut the relationship is linear!!! no? so correct option must be C. In D there was a curve, so it cannot be D. Sorry, the volumes are not equal, i get that now, but they are proportionate i guess.
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