it's not electrode B? :OAgain,that question..The question was exactly like this
In both cases,electrolysis and cell,the cathode is where a REDCUTION reaction takes place and anode is where oxidation takes place.
In case of electrolysis,the anode is positive and cathode is negative.
The opposite occurs in a cell,where the more reactive metal loses electrons so it the negative pole and therefore ANODE.
Here there were no metals but the electrons flow was clearly shown,and the question stated
"Which electrode will be oxidized and decrease in mass"
Electrode B,Loses electrons ,dissolve in the solution as ions and its mass decreases(This actually ressembles electroplating where the ANODE loses electrons and change into ions.
While Electrode A,also decreases in mass but due to reaction with oxygen..This electrons compensate those lost in the reaction with oxygen which is A REDOX REACTION.
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Chemistry P31
- Thread starter bluefa1con
- Start date
huh ?If you are speaking about the diagram it's not the same.
what's the answer?
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man, i'm confused!
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what's the answer?
I thought you told me not to worry!you're the one who's crying now.
hey it's for 3 marks :|
you're the one who's crying now.
me too, is that correct?
oh i was confused about it, but i got it 11
electron distribution would be 8 because u can never put 11 or 12 u can only put 2-8-18-32 etc........ and it was previously mentioned that vanadium has variable oxidation states so putting 8 was correct as then it would have oxidation state of +3
- Messages
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oh!
- Messages
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the answer was 8
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lol i guess no more than 7 which is good for meHow many marks do u think u lost until now? Im asking coz I consider u to be like an A* student
wbu?and btw thats the upper bond
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Guys yeah the M.P and B.P decrese down the group and the second answer idr the Q ...It was Francium
- Messages
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that's what i wrote!Guys yeah the M.P and B.P decrese down the group and the second answer idr the Q ...It was Francium