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hehe its okiiohhh sorry i thought u didnt did Cl- to the power of 2 Sorry once again
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hehe its okiiohhh sorry i thought u didnt did Cl- to the power of 2 Sorry once again
You need to read the instructions clearly Have a copy of the syllabus next to you as you read.I looked through it but it doesnt clearly differentiate between teh AS and the A2 components
There isn't much to this question other than trying to figure out how you could use atoms/elements in the original compound (ammonium nitrate) to make fragments that would add up to each of the peaks in the question. My initial hunch was that A and B would be NH3 and NO2, but those don't balance (I mean even if only one mole of these gases is made, the Mr of NH4NO3 - 62 - is not equal to the combined Mr of both product gases - 17 + 46 = 63, so this must be dismissed.) Instead, chose two gases that would separately make up the maximum m/e values, 18 and 44 using onlu the elements provided. These would be H2O (18) and N2O (44). They even balance! 18 + 44 = 62. Then you can break these up to make each of the smaller values: O+ = 16, OH+ = 17. And N+ = 14, O+ = 16, N2+ = 28, NO+ = 30. (They'll all have positive signs 'cause the spectrometer only deals with positive ions.)
questions of this type is really annoying because it takes a lot of time to figure out the fragment by trying to multiply the atoms with each other till u get the given Mr so its a big waste of time i see. i would suggest that if a question of this type came in the exam, leave it to the last. its better to waste 5-6 marks instead of leaving 3 full questions or somehting because a question of this type will just waste ur whole time to figure it out..anyone else agrees?Asalamo Alaikum everyone!
Can anyone please help me with this A2 question:-
Q 3 part d(ii) of this paper?
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s10_qp_42.pdf
umm...xhizors i think we need you hereAoa wr wb
Can someone please help me with these doubts?
Qn 9 b and d )
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_y07_sp_4.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_y07_sm_4.pdf
Qn 9 c ii)
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w07_qp_4.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w07_ms_4.pdf
Qn 7 c ii )
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w09_qp_41.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w09_ms_41.pdf
I would really appreciate if you could provide a detailed explanation for these NMR questions
JazakAllah khair, thanx a lot
ohhh srsly i too hav the same dbts :O plzz helpAoa wr wb
Can someone please help me with these doubts?
Qn 9 b and d )
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_y07_sp_4.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_y07_sm_4.pdf
Qn 9 c ii)
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w07_qp_4.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w07_ms_4.pdf
Qn 7 c ii )
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w09_qp_41.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w09_ms_41.pdf
I would really appreciate if you could provide a detailed explanation for these NMR questions
JazakAllah khair, thanx a lot
Soldier313 how long can u wait? I'll study it and then tell you...Aoa wr wb
Can someone please help me with these doubts?
Qn 9 b and d )
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_y07_sp_4.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_y07_sm_4.pdf
Qn 9 c ii)
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w07_qp_4.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w07_ms_4.pdf
Qn 7 c ii )
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w09_qp_41.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w09_ms_41.pdf
I would really appreciate if you could provide a detailed explanation for these NMR questions
JazakAllah khair, thanx a lot
I can wait a while Thank youSoldier313 how long can u wait? I'll study it and then tell you...
i will talk about the first question u have postedAoa wr wb
Can someone please help me with these doubts?
Qn 9 b and d )
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_y07_sp_4.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_y07_sm_4.pdf
Qn 9 c ii)
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w07_qp_4.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w07_ms_4.pdf
Qn 7 c ii )
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w09_qp_41.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w09_ms_41.pdf
I would really appreciate if you could provide a detailed explanation for these NMR questions
JazakAllah khair, thanx a lot
i will talk about the first question u have posted
b) first of all u try to identify the type of proton on each peak.. the numbers on the top of the peak tells u how many hydrogen proton is present in the type of proton..and i believe u do have a data booklet so u can check how the type of protons look like at the chemical shift given..
the first peak at approx 1.2-1.3 shows that it has 3 hydrogen protons and it is split into triplet which means the adjacent carbon must have 2 hydrogen protons on it because of the rule we need to learn (n+1) where n is the number of hydrogen protons on the adjacent carbon. so we have a peak of RCH3 because thats the only one available in the data booklet which has 3 hydrogen protons.
now the peak at approx 2.1 shows that it has 2 hydrogen proton on it so it can be CH2 and it is CH2 because the peak at 1.2-1.3 shows that the adjacent carbon is split into 3 which means the adjacent carbon has 2 hydrogen so yeah t must be CH2 now this speak is split into quartet which means there is 3 hydrogen protons on the adjacent carbon and this is true because see RCH3 at peak 1.2-1.3 has 3 hydrogen carbons..so we can guess we have RCH2R and RCH3 now obviously the peak at 5.5 is OH because this speak always shows as single and doesnt split if u look at the last one (check in the data booklet) it is a benzene ring with a phenol group attached to it but beware that this peak shows that it has 4 hydrogen protons so there are 2 hydrogen which has been removed from the benzene ring. one substituted with a phenol group and the other one will be CH2CH3 so our molecule will be
HO-C6H4-CH2CH3 see the benzene ring peak is split into 4 quartet also and u can see that it is next to a molecule which has one proton and another molecule which has 2 protons so 3+1 using the n+1 rule will split this peak into 4!! so yeah our identification of the aromatic compound is correct
i really hope u understood it because it is very confusing to explain it on the internet instead of face to face
JazakAllah for this May ALLAH bless you in sha Allahi will talk about the first question u have posted
b) first of all u try to identify the type of proton on each peak.. the numbers on the top of the peak tells u how many hydrogen proton is present in the type of proton..and i believe u do have a data booklet so u can check how the type of protons look like at the chemical shift given..
the first peak at approx 1.2-1.3 shows that it has 3 hydrogen protons and it is split into triplet which means the adjacent carbon must have 2 hydrogen protons on it because of the rule we need to learn (n+1) where n is the number of hydrogen protons on the adjacent carbon. so we have a peak of RCH3 because thats the only one available in the data booklet which has 3 hydrogen protons.
now the peak at approx 2.1 shows that it has 2 hydrogen proton on it so it can be CH2 and it is CH2 because the peak at 1.2-1.3 shows that the adjacent carbon is split into 3 which means the adjacent carbon has 2 hydrogen so yeah t must be CH2 now this speak is split into quartet which means there is 3 hydrogen protons on the adjacent carbon and this is true because see RCH3 at peak 1.2-1.3 has 3 hydrogen carbons..so we can guess we have RCH2R and RCH3 now obviously the peak at 5.5 is OH because this speak always shows as single and doesnt split if u look at the last one (check in the data booklet) it is a benzene ring with a phenol group attached to it but beware that this peak shows that it has 4 hydrogen protons so there are 2 hydrogen which has been removed from the benzene ring. one substituted with a phenol group and the other one will be CH2CH3 so our molecule will be
HO-C6H4-CH2CH3 see the benzene ring peak is split into 4 quartet also and u can see that it is next to a molecule which has one proton and another molecule which has 2 protons so 3+1 using the n+1 rule will split this peak into 4!! so yeah our identification of the aromatic compound is correct
i really hope u understood it because it is very confusing to explain it on the internet instead of face to face
thanksss pray for me pls i am solving the other 2 now !This is amazing! it's exactly what i wanted!
JazakAllah khair ! May Allah bless you inshaAllah!
merciiiii zariJazakAllah for this May ALLAH bless you in sha Allah
for the second question u have posted..Aoa wr wb
Can someone please help me with these doubts?
Qn 9 b and d )
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_y07_sp_4.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_y07_sm_4.pdf
Qn 9 c ii)
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w07_qp_4.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w07_ms_4.pdf
Qn 7 c ii )
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w09_qp_41.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w09_ms_41.pdf
I would really appreciate if you could provide a detailed explanation for these NMR questions
JazakAllah khair, thanx a lot
the final question!!Aoa wr wb
Can someone please help me with these doubts?
Qn 9 b and d )
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_y07_sp_4.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_y07_sm_4.pdf
Qn 9 c ii)
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w07_qp_4.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w07_ms_4.pdf
Qn 7 c ii )
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w09_qp_41.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w09_ms_41.pdf
I would really appreciate if you could provide a detailed explanation for these NMR questions
JazakAllah khair, thanx a lot
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