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Chemistry: Post your doubts here!

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hassam

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I is for competitve inhibition.....and II for non-competitive......why is rate for non-competitive higher than competitve but lower than normal....?
 

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omg

omg

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can i get the mark scheme ov nov 2011 p53 and p51!! its nt there in the paper sec!! pls i need it urgently
 
Just call me MJ

Just call me MJ

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hassam said:
I is for competitve inhibition.....and II for non-competitive......why is rate for non-competitive higher than competitive but lower than normal....?
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Both competitive and non competitive inhibit the reaction of the enzymes in one or more ways. the competitive inhibitors compete with the substrates for the active site of the enzyme, and once they enter the enzyme's active site, they act like substrates, and the other substrates have to "wait" for the inhibitors to be broken down, to replace them. thats why the reaction rate becomes constant for some time, and thats why its rate of reaction is almost half of that of the normal.

Non competitive inhibitors attach themselves to other parts of the enzyme, inhibiting its function in an indirect way, but the enzyme itself can still act on the substrate. because of the non competitive inhibitors the enzymes have a lower rate of reaction than that of the normal, since enzymes can't function at "full power" :) Makes sense?!? o_O
 
smzimran

smzimran

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Any notes regarding applications, anyone? It is not given very well in the application booklet.
 
abcde

abcde

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smzimran said:
I am very bad at rote-learning. :(
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Don't call it rote learning! Make notes, reference cards - basically anything that makes the content stick in your mind. Make it 'stick' not by rote-learning but by comprehension/understanding.
 
abcde

abcde

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smzimran

smzimran

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abcde said:
Don't call it rote learning! Make notes, reference cards - basically anything that makes the content stick in your mind. Make it 'stick' not by rote-learning but by comprehension/understanding.
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Hmmm.....:)
 
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Doctor Nemo

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smzimran said:
Hmmm.....:)
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Sorry, I was being sarcastic. The Chemistry Applications booklet is rather poor. The newer version looks better and seems to have less excess material that you do not need to know. Make sure you are using that version.

Much of the material can be found in biology books for example. If you do not understand the material in the booklet then try reading about the same material in another book. It sometimes helps to read another version about the material.
 
smzimran

smzimran

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Doctor Nemo said:
Sorry, I was being sarcastic. The Chemistry Applications booklet is rather poor. The newer version looks better and seems to have less excess material that you do not need to know. Make sure you are using that version.

Much of the material can be found in biology books for example. If you do not understand the material in the booklet then try reading about the same material in another book. It sometimes helps to read another version about the material.
Click to expand...
I am using the latest one I suppose...and by the way, thanks
 
Just call me MJ

Just call me MJ

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Can somebody explain question 8 paper1 may/june 2003! Its soooooo annoying!! when you think you could answer 1 paper without a single mistake and you get the exact opposite!
 
Vogue

Vogue

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In a titration between an acid (in burette) and an alkali, you may need to re-use the same titration flask.
Which is the best procedure for rinsing the flask?
A. Rinse with distilled water and then with the alkali.
B. Rinse with tap water and then with distilled water
C. Rinse with tap water and then with the acid.
D. Rinse with the alkali.

and another question is dat how come many carbonates react with acids when all carbonates are insolube except ammonium, potassium and sodium.......?
 
abcde

abcde

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MEGUSTA_xD said:
http://www.xtremepapers.com/CIE/International A And AS Level/9701 - Chemistry/9701_s03_qp_1.pdf
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This question has to do with simply writing down the oxidation state of nitrogen first in the reactant compound and then the product compound. After that, you just have to compare the oxidation state changes. Working out the oxidation state is taught during O'level Chemistry. Here are the changes:
A: -3 -----> + 2 ( a change of 2-(-3) = 5)
B: +4 -----> +5 (a change of 1)
C: +2 -----> +4 (a change of 2)
D: -3 -----> 0 ( a change of 3) and +2 -----> 0 (a change of -2).
The greatest change occurs in A. Thus, 'A' is correct.
 
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