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Chemistry: Post your doubts here!

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Need help! why is the product at anode for MgBr is Br2? Isn't it suppose to be oxygen?
 
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271
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Plz help me with these questions
May June 2006 paper 4
Q4 diii
Q4 e(if I join tyrosine- lysine-glycine,will it also be fine)
Q5 part a reaction 1,I am confused when do we add only HNO3 and when add both HNO3 and H2SO4.
Thanks alot!
 
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34:

I'd go with B. 3 is definitely wrong because calcium IONS wont react with H+, but solid will. 1 and 2 are correct. 2 is most definitely correct, and so I'm left with B.

35:
1- It does.
2- It does.
3- It doesn't because it's basic itself.

so, A

36:
B?

1- It is. NaClO3.
2- It does. +5 in NaClO3 and -1*5 in 5NaCl.
3- It doesn't. It's going from 6*+1 to +1 and 5*+1 so definitely not [R].

Thanks too much ^_^
 
Messages
253
Reaction score
1,195
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153
Plz help me with these questions
May June 2006 paper 4
Q4 diii
Q4 e(if I join tyrosine- lysine-glycine,will it also be fine)
Q5 part a reaction 1,I am confused when do we add only HNO3 and when add both HNO3 and H2SO4.
Thanks alot!
in 4e u can join the amino acids in any order but there should be 3 amino acids present and 2 peptide bonds present
hmmm we use only dilute HNO3 when theres reaction with a phenol and H2SO4 and HNO3 when theres benzene or whtever got it?
 
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Need help! why is the product at anode for MgBr is Br2? Isn't it suppose to be oxygen?
the half equation will be .....02+2H2O+4e=4OH.....and Br2+2e=2Br.....and if u look the E values.......OH- has greater tendency to get oxidised.......Remember this OH- comes from the dissociation of H2O present in the solution
 
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302
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the half equation will be .....02+2H2O+4e=4OH.....and Br2+2e=2Br.....and if u look the E values.......OH- has greater tendency to get oxidised.......Remember this OH- comes from the dissociation of H2O present in the solution
Can you elaborate the point ? or compare it with the other two ? For cathode > more positive E vlaue will go to cathode and no doubt in that ..
What about anode?
 
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