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Can anyone help please and Expla
in this ?
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Nitrogen will exist as N3- ion....so it will have total of 10 electrons....so, the answer is DThanks and If you don't matter can you explain this one too !
I didn't get it , how 10 electrons ?!Nitrogen will exist as N3- ion....so it will have total of 10 electrons....so, the answer is D
GaN in which Ga exists as 3+ so N must exist as N3-, and it now it has 3 more eletrons...so total of 10I didn't get it , how 10 electrons ?!
Thanks .. you seem genius in chemistry mashallah Can you help me in my posted questions too if you don't mind ^_^GaN in which Ga exists as 3+ so N must exist as N3-, and it now it has 3 more eletrons...so total of 10
Hydrogen bond is between hydrogen and highly electronegative ion ( N , O , F ) .. so B only has this H --- N in ammonia
If you look at the 2nd reaction the double bond in aldehyde is being attacked by CH3CH2O-, which is a nucleophile, and it involves formation of a single product, so it is nucleophilic additionCan anyone help please and Explain this ?
See if you can help with this :"Hydrogen bond is between hydrogen and highly electronegative ion ( N , O , F )" Not ion! ^^
they r not in diff directions.... in beta pleated hydrogen bonds form btw diff polypeptide chains and the r diff polypeptide chains
this diagram is lso given in my TB
please some one help me http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s06_qp_1.pdf
Q23 , Q20 , Q15 , Q17 , Q11 , Q5 , Q6 , Q3 ... answer as much as you can .. so that I don't disturb you and inbox me if required thanks ^_^
You're awesome <3 That helped me a lot3 - D
Na3- so gains 3 electrons.
1s2 2s2 2p6
5 B
Hydrogen bonding exists b/w compounds containing N/O/F.
6 A
Almost picked D overlooking ammonia but it'll be A bec ammonia has Hydrogen Bonding.
11 A?
I'd go with A. OH- produced would react with the H+ ions added to form H2O again which would produce even more HOCl. B will maintain a high conc too, but A will maintain a higher concentration.
15 A
Most definitely A.
AlCl3 exists as a dimer at high temperatures, with the Cl lone pair forming a dative bond with Al.
17 C
Group 7 [O] review.
Cl2 + 2I- -> 2Cl- + I2
20 C?
A and D are out. Always hated these messed up nucleophile electrophile terms. I always mix them up and have to associate them with the word 'pedophile' to realize what they mean.
I guess it's nucleophilic addition because the aldehyde is undergoing a nucleophilic addition reaction. Idk.
23 C in a heartbeat!
A-> Ethanol CH3CH2OH = 46
B-> Ethene CH2=CH2 = 28
C-> Interesting. It can form CH3CH2BR and up to CBr3CBr3. In any case, it'll be this because Br alone > 64.5. I knew this from the many Br79-81 questions I've done so I selected this right away. Done each step to explain.
D-> Chloroethane CH3CH2Cl = 64.5
Can anyone help me please how did we get this ?!
Can anyone help me please how did we get this ?!
Shokran ^_^group II metal nitrate is going to produce metal oxide and nitrogen dioxide gas,the ratio between metal nitrate and metal oxide would be 1:1
5/x+28+96 = (5-3.29)/x+16
equate it u will get the answer
Thank's BroOh boy. That's a toughie.
Group II metal nitrate upon heating will produce a metaloxide and NO2 in 1:1
X(NO3)2 -> XO + NO2
Umm. I'd probably tackle it by finding the mols of the metal nitrate and metal oxide in terms of x.
5/(x+(2(14+16*3)=5-3.29/(x+16)
5/x+124 = 1.71/x+16
5x+80 = 1.71x + 212.04
3.29x = 132.04
x = 40.1
so, Calcium.
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