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Chemistry: Post your doubts here!

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Can you elaborate the point ? or compare it with the other two ? For cathode > more positive E vlaue will go to cathode and no doubt in that ..
What about anode?
Ok....for cathode the two candidates are Mg2+ and H+ and according to E values ...H+ has more tendency to get reduced ....and for anode....at anode,oxidation occurs...so,the candidates are OH- and Br-....now, for cathode, if E values is positive, than that elements will get reduced.....and for anode, those elements having negative E vales will get oxidised.........
 
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Hi guys,want to ask smthg.
How do i see which is identical.All seems same for me.Haha
The answer is j
 

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Hei guys.Can anyone help me with this terribly hard question from may june 13 paper.Thank u.
My doubts r the last 3 reaction.
a)how can the 6th rxn be a ligand exchange
b)how can the last rxn show a ligand exchange n no acid base.Isnt there suppose to be acid base when got prescence of water as product.Thanks a lot.....
 

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Ok....for cathode the two candidates are Mg2+ and H+ and according to E values ...H+ has more tendency to get reduced ....and for anode....at anode,oxidation occurs...so,the candidates are OH- and Br-....now, for cathode, if E values is positive, than that elements will get reduced.....and for anode, those elements having negative E vales will get oxidised.........
02+2H2O+4e=4OH- E value is +0.40V
Br2+2e=2Br E value is + 1.07V

OH has lower ( more negative ) Evalue , so it will be at anode ???????
 
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OH- oxidises to give O2........you must be knowing that metals goes to cathode and non metal to anode......and at anode, oxidation takes place....and according to our E values, less positive have more tendency to get oxidised...
 
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OH- oxidises to give O2........you must be knowing that metals goes to cathode and non metal to anode......and at anode, oxidation takes place....and according to our E values, less positive have more tendency to get oxidised...
My friend you said it , " less positive have more tendency to get oxidised... "
So its oxygen which will be at anode ( less positive E value ) NOT Br .. :LOL:
 
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in 4e u can join the amino acids in any order but there should be 3 amino acids present and 2 peptide bonds present
hmmm we use only dilute HNO3 when theres reaction with a phenol and H2SO4 and HNO3 when theres benzene or whtever got it?
Thanks a lot!what if there is a methyl group at position 1 and OH at position 4 in benzene ring what will I use for nitration?
Reminder for the alpha helix structure( plz a simpler one)
Thanks
 
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My friend you said it , " less positive have more tendency to get oxidised... "
So its oxygen which will be at anode ( less positive E value ) NOT Br .. :LOL:
Ahhhh...what did i do up there......sorry....i,myself got pretty confused ....let me think....:p
 
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BY1W0k.png


Please Help me !!!
 
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Thanks a lot!what if there is a methyl group at position 1 and OH at position 4 in benzene ring what will I use for nitration?
Reminder for the alpha helix structure( plz a simpler one)
Thanks
no matter wht else is present as far as ik if OH is present then for nitration u use dilute HNO3
yh i posted tht n u saw it also :p
 
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Its , Cl2 + KI ---> KCl + I2
Oxidation state of element is zero .. and in KI oxidation state of iodine is -1 ... therefore it changes from -1 to 0 ( increase in oxidation state ) which is oxidation
Thanks :) and If you don't matter can you explain this one too ! :)
2yqqaz.png
 
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My friend you said it , " less positive have more tendency to get oxidised... "
So its oxygen which will be at anode ( less positive E value ) NOT Br .. :LOL:
My friend, i tried doing it using the E values......but, i did not match with what we have actually studied...but on our coursebook, an list of increasing ease of oxidation of elements are given...see that...it will help you
 
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