http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s13_qp_42.pdf
Anyone generous to help
Q2 part b
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s13_qp_42.pdf
Anyone generous to help
Q2 part b
Ok....for cathode the two candidates are Mg2+ and H+ and according to E values ...H+ has more tendency to get reduced ....and for anode....at anode,oxidation occurs...so,the candidates are OH- and Br-....now, for cathode, if E values is positive, than that elements will get reduced.....and for anode, those elements having negative E vales will get oxidised.........Can you elaborate the point ? or compare it with the other two ? For cathode > more positive E vlaue will go to cathode and no doubt in that ..
What about anode?
02+2H2O+4e=4OH- E value is +0.40VOk....for cathode the two candidates are Mg2+ and H+ and according to E values ...H+ has more tendency to get reduced ....and for anode....at anode,oxidation occurs...so,the candidates are OH- and Br-....now, for cathode, if E values is positive, than that elements will get reduced.....and for anode, those elements having negative E vales will get oxidised.........
My friend you said it , " less positive have more tendency to get oxidised... "OH- oxidises to give O2........you must be knowing that metals goes to cathode and non metal to anode......and at anode, oxidation takes place....and according to our E values, less positive have more tendency to get oxidised...
Thanks a lot!what if there is a methyl group at position 1 and OH at position 4 in benzene ring what will I use for nitration?in 4e u can join the amino acids in any order but there should be 3 amino acids present and 2 peptide bonds present
hmmm we use only dilute HNO3 when theres reaction with a phenol and H2SO4 and HNO3 when theres benzene or whtever got it?
Thanks! Yeah it is simple (a bit)the first one is complicated but the second one has to be drawn in the exam n its quite simple i belief wht do u think?
Ahhhh...what did i do up there......sorry....i,myself got pretty confused ....let me think....My friend you said it , " less positive have more tendency to get oxidised... "
So its oxygen which will be at anode ( less positive E value ) NOT Br ..
cudnt expect to be any more simpler afterall we r doing A2 not KG2Thanks! Yeah it is simple (a bit)
Thanks again!
no matter wht else is present as far as ik if OH is present then for nitration u use dilute HNO3Thanks a lot!what if there is a methyl group at position 1 and OH at position 4 in benzene ring what will I use for nitration?
Reminder for the alpha helix structure( plz a simpler one)
Thanks
Hydrogen bond is between hydrogen and highly electronegative ion ( N , O , F ) .. so B only has this H --- N in ammonia
Please Help me !!!
Its , Cl2 + KI ---> KCl + I2
Help me please !
Thanks and If you don't matter can you explain this one too !Its , Cl2 + KI ---> KCl + I2
Oxidation state of element is zero .. and in KI oxidation state of iodine is -1 ... therefore it changes from -1 to 0 ( increase in oxidation state ) which is oxidation
My friend, i tried doing it using the E values......but, i did not match with what we have actually studied...but on our coursebook, an list of increasing ease of oxidation of elements are given...see that...it will help youMy friend you said it , " less positive have more tendency to get oxidised... "
So its oxygen which will be at anode ( less positive E value ) NOT Br ..
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now