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Chemistry: Post your doubts here!

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Q29:- (D) Because Cold one Breaks double Bond and Forms Diol (two OH groups added ) giving two chiral centers. And with Hot KMnO4 it disrupts the double bind completely which causes this compound to lose one chiral center!
What happened by hot KMnO4 exactly ?
 
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Do you have anything like that but for physics?

As a matter of fact, I do.
Gimme a day. I'll gather up all the individual facesheets, merge them and upload them and send you the link.
Or, if you want specific topics, let me know and I'll send you those.
 
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w

hat do you mean by the best yield ?
Best yeild mean produces Only 2-chloropropane, No other Chloropropanes.
A. will give you both monochloro propanes and a bunch of di- and trichloro as well.
B. will give NO REACTION
C. is correct, the desired compound is the sole product.
D. would give more 2-propanol than 2-chloropropane. (if anything)
 
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Cleavage occurs and the double bond is split.

If the side being split is CH2, it forms CO2+H2O. If it's CHR then it forms COOH. If it's CRR' then it forms a Ketone. Get it?
Yeah thanks alot ! .. btw Is it true that the first 5 alkanes are gases !? because It is the first time for me to hear that !
 
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