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Chemistry: Post your doubts here!

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I got it ^^ what about Q26
Since it was partial oxidation of the primary alcohol, the aldehyde was produced.
Number of moles of ethanol: 2.30/46 is 0.05
One mole of ethanol produce 1 mole of aldehyde CH3CHO
The theoretical mass of the aldehyde will be 0.05*44 is 2.2 g
The actual mass produce is 70%.
 
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Since it was partial oxidation of the primary alcohol, the aldehyde was produced.
Number of moles of ethanol: 2.30/46 is 0.05
One mole of ethanol produce 1 mole of aldehyde CH3CHO
The theoretical mass of the aldehyde will be 0.05*44 is 2.2 g
The actual mass produce is 70%.
Ops .. my bad X) .. I thought it is carboxylic acid .. I skipped the word distillation .. :p anyways thanks :)
 
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O/N_2004_P1 -- Q9, Q12, Q13, Q39

M/J _2006_P1 -- Q32

M/J_2011_P12 -- Q8

O/N_2011_P12 -- Q26

M/J_2012_P12 -- Q5 , Q28 , Q36

Please someone help me I'm dying here from confusion !!! :cry::cry::confused:
O/N_2004_P1 -- Q9
A is incorrect because there is hydrogen bond exist in alocohol and is stable. The carboxylic and ketoes in options C and D are liquid because of intereating involving induces dipoles. We left with the alkane gas and if you remember, it is only reaction they are good at.

Q12 of same year
clip_image001.jpg

Well you can see the affect of temperature here
I stuck on Q39:(.
 
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O/N_2004_P1 -- Q9
A is incorrect because there is hydrogen bond exist in alocohol and is stable. The carboxylic and ketoes in options C and D are liquid because of intereating involving induces dipoles. We left with the alkane gas and if you remember, it is only reaction they are good at.

Q12 of same year
clip_image001.jpg

Well you can see the affect of temperature here
I stuck on Q39:(.
Q12 pic can you upload it again because file not found and for Q9 the question is asking about which will release the greatest energy so how did we skip the A, B, C options as they have H-C and C=O bonds which have more enery than those C-H bonds in option B !! I didn't get it
 
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O/N_2004_P1 -- Q9, Q12, Q13, Q39

M/J _2006_P1 -- Q32

M/J_2011_P12 -- Q8

O/N_2011_P12 -- Q26

M/J_2012_P12 -- Q5 , Q28 , Q36

Please someone help me I'm dying here from confusion !!! :cry::cry::confused:
M/J _2006_P1 -- Q32
Ans Is B.
1. It says enthalpy change of atomisation, yes we need to Know because Na(s) is converted to Na(g)
2. says Ionisation energy, we need Ionisation energy because it is converted from Na(g)(neutral) to Na(g)(Positive ione)
3. We dont need it because formation if for compounds not elements! So only 1 and 2!!
Hope I Helped!! :)
 
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Q12 pic can you upload it again because file not found and for Q9 the question is asking about which will release the greatest energy so how did we skip the A, B, C options as they have H-C and C=O bonds which have more enery than those C-H bonds in option B !! I didn't get it
Alkanes are fuel .
 
Messages
398
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761
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O/N_2004_P1 -- Q9, Q12, Q13, Q39

M/J_2011_P12 -- Q8

O/N_2011_P12 -- Q26

O/N_2009_P12 -- Q10 , Q20, Q28


M/J_2012_P12 -- Q5 , Q28 , Q36

Please someone help me I'm dying here from confusion !!! :cry::cry::confused:
O/N_2011_P12 -- Q26
Ethanol is converted to Ehanal (aldehyde)
First find moles of ethanol
:-
Moles=mass/Mr
Mass=2.3g..... Mr=46 (C2H5OH)
Moles=0.05
Now find mass of aldehyde:-
Mass=mole * Mr
Mole=0.05...... Mr=44(C2H4O)
Mass=2.2g
But question says yeild is 70%
so 70/100 * 2.2 =1.54 which Is A!!
Hope I Helped! :)
 
Messages
398
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O/N_2004_P1 -- Q9, Q12, Q13, Q39

O/N_2009_P12 -- Q10 , Q20, Q28, Q34, Q38 , Q40

M/J_2012_P12 -- Q5 , Q28 , Q36

Please someone help me I'm dying here from confusion !!! :cry::cry::confused:
M/J_2012_P12 -- Q5 , Q28 , Q36
Q5:-(A) Iodine because it has covalent bonds (I2) and vanderwaals forces!
Q36:-(D)Because haber process is N2 + 3 H2 → 2 NH3 (ΔH = −92.4 kJ·mol−1)
so Forward reaction is exothermic, if u Increase temp yeild goes Down, but Rate increases because Particles gain K.e. So 1 is Correct!
2 says High Pressure decreases yeild, thats wrong because High pressure favours side with less moles which is forward , this would increase yeild.
If 2 is Wrong then option is D! (no need to look at 3)
 
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Messages
398
Reaction score
761
Points
73
O/N_2004_P1 -- Q9, Q12, Q13, Q39

O/N_2009_P12 -- Q10 , Q20, Q28, Q34, Q38 , Q40

M/J_2012_P12 -- Q28

Please someone help me I'm dying here from confusion !!! :cry::cry::confused:
O/N_2009_P12 -- Q10 , Q20, Q28, Q34, Q38 , Q40
Q40:- (C) 1. it says one monomer would form polymer? how is that posible? so 1 is wrong then automatically answer is C.
Q38:-C ,Ethanol is oxidized by KMnO4 Not Alumina. so 1 is wrong. then automatically answer is C.
;)
 
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