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O/N_2004_P1 -- Q9, Q12, Q13, Q39O/N_2004_P1 -- Q9, Q12, Q13, Q39
O/N_2009_P12 -- Q10 , Q20
M/J_2012_P12 -- Q28
Please someone help me I'm dying here from confusion !!!
I will start with D
First write down the equation:-
........................ 2P ------ Q + 2R
Initial Moles= 2 (P) 0(Q) 0(R)
It is given in the question x moles of R at Equilibrium, so we could find moles of Q using Mole ratio.For P since P:R is 2:2=1:1 Then P would be Initial moles - the moles of R at Equilibrium.
Equil Moles= (2-x )(P) ( x/2 ) (Q) ( x)(R)
Total (Add them up) = 2-x+(x/2)+x = (2+x/2) so the ans is D
If u Need further explaination Do tell Me!
Hope i helped!
Thank Yew.. Glad You understoodWhat a brilliant explanation i have been trying to figure this out since 2 days
Great explanation
for question 9 it is not possible by bond energy thingy and for Q12 isn't the graph supposed to be shifted to right ? and for Q13 why Al2O3 not possible ?!O/N_2004_P1 -- Q9, Q12, Q13, Q39
Q9:-(B) Because it is alkane and alkanes produce max energy! i think u could also do this in terms of bond energy which is time consuming
Q12:-(B)https://www.xtremepapers.com/community/attachments/upload_2014-4-25_12-27-47-png.40167/
Q13:-(D) Because it should be With an alkali which is NaOH. (MgOH is Insoluble!)
Q39:-(D) This cant be dehydrated because the Carbon next to CH3OH has No Hydrogens so it cant be dehydrated. so 2 is Worng.
Then Ans is D!!
Yes I would be glad to Help..
ISA!!!Al2O3 is Solid!
What about D !!
Its alright i would try as much as possible. But i wont promise to do them On Time!
As u Like, Better if U post it here, Others May Help Out Tooo
!!I m Doing 21! Why not post it here?
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