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donno wht mistake am i committing
View attachment 45079
is the answer B? if so then it means reaction 1 is endo as it requires heat to decompose calcium carbonate, and reaction 2 is exo in nature as hydration is always exo
Yes it is B, but isn't reaction 2 a reaction enthalpy of a solution and can you please give me the definition of enthalpy of hydration.is the answer B? if so then it means reaction 1 is endo as it requires heat to decompose calcium carbonate, and reaction 2 is exo in nature as hydration is always exo
The enthalpy change of solution is the enthalpy change when 1 mole of an ionic substance dissolves in water to give a solution of infinite dilution.is the answer B? if so then it means reaction 1 is endo as it requires heat to decompose calcium carbonate, and reaction 2 is exo in nature as hydration is always exo
The heat energy released when new bonds are made between the ions and water molecules is known as the hydration enthalpy of the ion.Yes it is B, but isn't reaction 2 a reaction enthalpy of a solution and can you please give me the definition of enthalpy of hydration.
The enthalpy change of solution is the enthalpy change when 1 mole of an ionic substance dissolves in water to give a solution of infinite dilution.
and secondly in my opinion , heat of solution is the difference between lattice dissociation enthalpy and hydration enthalpyThe heat energy released when new bonds are made between the ions and water molecules is known as the hydration enthalpy of the ion.
The hydration enthalpy is the enthalpy change when 1 mole of gaseous ions dissolve in sufficient water to give an infinitely dilute solution. Hydration enthalpies are always negative.
The enthalpy change of solution is the enthalpy change when 1 mole of an ionic substance dissolves in water to give a solution of infinite dilution.and secondly in my opinion , heat of solution is the difference between lattice dissociation enthalpy and hydration enthalpy
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s08_qp_1.pdf
question 2 and 6 please help T_T
sometimes two humps also represent sn2 wat to doq 39
74.00g of butan-2-ol → 44.64 g of butanone
Moles of butan -2 -ol =1
moles of butanone= Mass/mr
=44.64/72= 0.62
now in theory 1 mole of butan 2 ol produces 1 mole of butanone.
but we got 0.62 moles of butanone
hence 62 percent yield
Use the same method for the rest of the reactions and you will gt 62 percent yield for all of them.
q 40
(CH3)3CBr + NaOH → (CH3)3COH + NaBr
(CH3)3CBr is a tertiary haloalkane .
It has three R groups attached to the Carbon bonded to the halogen
Only Tertiary haloalkanes undergo SN1 mechanism for nucleophillic substituition.
This is because tertiary haloalkanes have electron donationg methyl groups attached they can form an intermediate and stable carbocation.
The graph has two humps so this means that an intermediate is formed before the reaction proceeds.
2 and 3 are not tertiary haloalkanes so an intermediate is not formed
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