- Messages
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Look they said which one of them dsnt have lone pairs leftView attachment 45087 HELP!
Answer is C. I get what is going on in A and B. But could anyone help me understand C and D?
for Q2
15/100 x 14 =2.1g of N
basically it is the mole : the 15/100
So, 0.15 mole
And 0.15/5 = 0.03 dm3
3rd statement is a fact.
I have only done w13 13GUYSSSS. Gotta help me with this, PLEASEEE. hahahaha
Must be very easy for you guys!
Anyways, okay.
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w13_qp_13.pdf
Q27 (C)
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w13_qp_12.pdf
Q3 (B) Q8 (D) [ i guess all these answers correctly, but i dont understand why ]
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w12_qp_12.pdf
Q11 (A) [srsly no, what is this.]
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w11_qp_12.pdf
Q24 (B) , Q26 (A), Q30 (A)
THANK YOU SO SO MUCHHHHHH!! please help
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s11_qp_12.pdf
Q8-C Q10-C Q11-C Q19-A
Plz help
That helped,thanks for the effortQ8 whats the definition of enthalpy change of formation?
One mole of substance formed from its elements under standard conditions. So, its C! A and B definitely out since C in standard conditions should be in solid state.
Q10
Just look at Ca, Al and Si.
Do the empirical formula stuffs.
So, Ca= 14.04/40.1=0.35
Al= 14.17/27= 0.525
Si= 14.75/28.1=0.525
so you see, the mole ratio of Al and Si is the same, so you can straight eliminate B and D
Al and Si, both of them divided by 0.35 (cause it is the smallest mole ratio among three of them)
so 0.525/0.35=1.5
See the formula there, is Ca2 right? So, times 2. yeahhh it is 3. Hope you understand
Q11 it is posted somewhere like previous pages. or you just go and search google for the question. LOL SORRY trying to help but yeah, im rushing! WAIT I FOUND IT.
Moles of CO2=72/24000=0.003
moles of Al4C3= 0.003/3=0.001 (as ratio of Al4C3:CH4 is 1:3)
now mass of Al4C3= 0.001 into (27+27+27+27+12+12+12)=0.144g
Q19 idk whyyy
thanks, but i'm still confused :/Q21 The functional groups that react with Na are CO2H and OH, so three of any of these should be present in the compound. B and D are ruled out. NaOH will react with CO2H, so there should be 1 CO2H and 2 OH groups.
Na can react with both -CO2H and OH,thanks, but i'm still confused :/
I get D is ruled out butt how C I still umm :S :/
okay got a bit, but the part where yu said "but NaOH only with -CO2H so -1"Na can react with both -CO2H and OH,
there are 3 groups in C so -3 but NaOH only with -CO2H so -1
look at the charges
Na will react with both Na and COOH okay sookay got a bit, but the part where yu said "but NaOH only with -CO2H so -1"
tht I didn't get :/
Hydrolysis of the ester will give an carboxylic acid and alcohol
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