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Chemistry: Post your doubts here!

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Ok, guys. Its past midnight for me.

Time for me to log off.

If things go well, I might be back for the November batch, perhaps some of you might be kind enough to help them also since you have already ploughed through the questions in your current preparations.

All the best for your papers and your soon-to-be achieved freedom from exams. (y)
 
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This question please! :'(
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Ok, guys. Its past midnight for me.

Time for me to log off.

If things go well, I might be back for the November batch, perhaps some of you might be kind enough to help them also since you have already ploughed through the questions in your current preparations.

All the best for your papers and your soon-to-be achieved freedom from exams. (y)
Sir,I appreciate your help to all of us
THANKS :)
 
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Oct/ nov 2008
PLEASE HELP!!
Question 2 ans is C
4 answer is C
I don't understand 3 :$ answer is D
30 !! Answer is C

Please HELPPPP!!! :(
 
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In Kc we do not take the concentration of the solid. So in this case we will not include the concentration of Ag(s)
So it will be as follows:
Kc= (0.56) / (0.44^2)
= 2.89
That's option D
need help in this question
Q: flask X contain 1 dm3 of helium at 2kpa pressure and flask Y contain 2 dm3 of neon at 1kpa pressure.
if the flasks are connected at constant temperature, what is the final pressure?
A: 4/3 kpa
B:3/2 kpa
C; 5/3 kpa
D:2 kpa
how do we solve it and answer is A
 
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need help in this question
Q: flask X contain 1 dm3 of helium at 2kpa pressure and flask Y contain 2 dm3 of neon at 1kpa pressure.
if the flasks are connected at constant temperature, what is the final pressure?
A: 4/3 kpa
B:3/2 kpa
C; 5/3 kpa
D:2 kpa
how do we solve it and answer is A
according to boyle's law, p1v1 = p2v2
so when the 2 flask connect together, the total volume is now 1 + 2 = 3dm3
using the formula above , for flask X
- 1 x 2 = p x 3
- p = 2/3
for flask Y
- 2 x 1 = p x 3
- p = 2/3
therefore, the total pressure after both flask connect is 2/3 + 2/3 = 4/ 3
so answer is A.
 
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