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Chemistry: Post your doubts here!

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Two equilibria are shown below.

reaction I 2X2(g) + Y2(g) 2X2Y(g)
reaction II X2Y(g) X2(g) + )g( 2
1Y 2

The numerical value of Kc for reaction I is 2.

Under the same conditions, what is the numerical value of Kc for reaction II?
Answer is 1 over square root 2
 

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6- use PV=nRT to calculate number of moles
multiply the moles with Mr of Ammonia

q11- A, since if u divide the Enthalpy with N u will get of a single X-Y bond.
q17-calculate moles from PV=nRT
divide the mass by moles to get Mr and check against periodic table
21-D, since if you add C2H5, there will be two of them one one side, two C2H5 on the second Carbon and so no cis-trans.
24-c, cz u need to break the double bond and insert a OH on the second carbon which would be oxidised to ketone in the next step.
26-c, cz u need to remove a chlorine from one carbon and that same carbon has to be a radical
38-1 is correct, so is 2., basics. 3 is not because Alcohols dont undertake such substitution to form halogenoalkane
 
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i recently scored 40/40 in 31 minutes(physics paper) and then 39/40 in 41 minutes(chemistry)
when i started doing papers i was at 27. the marks increased with practice till maximum of 36/40. with more and more practice and if only i am totally awake when doing paper i score 38+ otherwise 37 is an average.
Chemistry June 2013, Paper 1_2 Question 31?? y A?
 
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3 In aqueous solution, the acid HIO disproportionates according to the following equation where m,
n, p and q are simple whole numbers in their lowest ratios.

mHIO → nI2 + pHIO3 + qH2O

This equation can be balanced using oxidation numbers.

What are the values for n and p?

n p
A 1 2
B 2 1
C 4 1
D 4 2
 
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3 In aqueous solution, the acid HIO disproportionates according to the following equation where m,
n, p and q are simple whole numbers in their lowest ratios.

mHIO → nI2 + pHIO3 + qH2O

This equation can be balanced using oxidation numbers.

What are the values for n and p?

n p
A 1 2
B 2 1
C 4 1
D 4 2
Here's the link to the solution. But i don't get it. Hope you do. Plz, explain to me too. :)
https://www.xtremepapers.com/commun...-for-chemistry-only.19324/page-23#post-609519
 
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