- Messages
- 1,983
- Reaction score
- 3,044
- Points
- 273
I'll start from begining If you will.5 (c) http://freeexampapers.com/A-Level/Chemistry/CIE/2012-Jun/9701_s12_ms_23.pdf
May/June/2012
Variant 23
I've attached the mark scheme! Please help guys, this question alone carries 4 marks :/
Only COOH reacts with carbonates so it has COOH group
SO by the information we have we can deduce structure of F
it has COOH, rest of it is C2H5O. if its has OH it will be CH3CH(OH)COOH. That fits all the information.
The type of reaction has to be oxidation because KMnO4 is an oxidising agent.
When H is treated with conc. H2SO4 it will be a dehydration reaction. So it will become CH2=CHCOOH. when oxidised with cold KMnO4 it becomes CH2(OH)CH(OH)COOH.
SO we have two groups in F that will react with Na. OH and COOH.
so one mole of F will react with 2 mol of Na to produce 2 H which is actually 2/2 H2 or 1 H2
That means that n(F)=n(H2).
n(F)=0.6/Mr and Mr=3(12)+6+3(16)=90
n(F)=0.006667 mol = n(H2)
volume = n*24 dm3 = 0.006667*24=0.16 dm3=160cm3
If anything is not clear feel free to ask without any hesitation.