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hey, why did u do left= right? beacuse the charges must be balanced on both sides of the eq?Ratio is 3:2
3Ti+ + 2V5+ -----> 3Ti3+ + 2V(?)+
Left = 3+2*5=13
Right=3*3+2*?=9+2*?
Left=right
13=9+2*?
?=2
Thankyou!Initial: b, 0, 0
Final: b-x, x/2, x/2
Total moles = b-x+x/2+x/2= b
Mole ratio: (b-x)/b, (x/2)/b, (x/2)/b
Partial pressure = p(b-x)/b, px/(2b) px/(2b)
Kp = px/(2b)*px/(2b) / (p(b-x)/b)^2 = D
Alternatively you can realise that we can use concentration and find out Kp expression without taking pressure or mole ratio to consideration, since you can see Kp will have no units as pressure cancels out
Yeshey, why did u do left= right? beacuse the charges must be balanced on both sides of the eq?
It's DWhat's the answer?
Does anyone know the answer and the reason behind it?
View attachment 54338
Why is 3 wrong?
yea there wud high conc. of OH- ions but why wud it collide with Al and Ba(NO3)2 ? :SI think it might be because if the pH is 14, there is a very high concentration of hydroxide ions. This would lead to OH- ions having high chances of collision with the aluminum and barium nitrate. It's just a guess I'm not sure though
If B was to be true, then purple vapour would've formed with sodium iodide in the second row toowhy is B wrong?
Sulphur has a charge of +2 in this case, so S2O3 has a total charge of -2 which becomes -4 since there are two of them. The total charge of the entire molecule is -3, so Ag must be +1.how to find the oxidation state of Ag in this ion..? is shud come out to be +1:/ thou i'm getting -1
help!!!
Just wanna say again I'm not sure but:yea there wud high conc. of OH- ions but why wud it collide with Al and Ba(NO3)2 ? :S
n of ethanol : 0.05 : n of ethanal.
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