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Chemistry: Post your doubts here!

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Initial: b, 0, 0
Final: b-x, x/2, x/2
Total moles = b-x+x/2+x/2= b
Mole ratio: (b-x)/b, (x/2)/b, (x/2)/b
Partial pressure = p(b-x)/b, px/(2b) px/(2b)

Kp = px/(2b)*px/(2b) / (p(b-x)/b)^2 = D

Alternatively you can realise that we can use concentration and find out Kp expression without taking pressure or mole ratio to consideration, since you can see Kp will have no units as pressure cancels out
Thankyou! :D
 
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I think it might be because if the pH is 14, there is a very high concentration of hydroxide ions. This would lead to OH- ions having high chances of collision with the aluminum and barium nitrate. It's just a guess I'm not sure though
yea there wud high conc. of OH- ions but why wud it collide with Al and Ba(NO3)2 ? :S
 
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how to find the oxidation state of Ag in this ion..? is shud come out to be +1:/ thou i'm getting -1
help!!!
 

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why is B wrong?
If B was to be true, then purple vapour would've formed with sodium iodide in the second row too

how to find the oxidation state of Ag in this ion..? is shud come out to be +1:/ thou i'm getting -1
help!!!
Sulphur has a charge of +2 in this case, so S2O3 has a total charge of -2 which becomes -4 since there are two of them. The total charge of the entire molecule is -3, so Ag must be +1.
 
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yea there wud high conc. of OH- ions but why wud it collide with Al and Ba(NO3)2 ? :S
Just wanna say again I'm not sure but:
If aluminium hydroxide and barium hydroxide are being formed by reaction with water it's probably got to do with OH- ions from water forming dative bond with the metal atoms...
So if there is more such OH- ions in the mixture, there would probably be a higher rate of occurance for this bond formation... Due to random movement and collision and bla bla the high concentration of the OH- increases reaction rate. I suppose. I hope someone else has a more thorough answer.
 
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