Chemistry: Post your doubts here!

[A*****]

Look 1 mol is produced by cracking the ethene, methane n propene 0.5 mol of ethene already given in the question so we need to find the ratio of other products mol so like 0.5+0.25+0.25= 1 mole to convert it into whole number we just multiply with 4 so by adding them we will get 8 carbon altogether

Thanx bro!

 

[khadijaimran]

how do you do this please?

 

[Hamnah Zahoor]

how do you do this please?

Ester breakage of the compound will help you identify it.

 

[khadijaimran]

t

View attachment 63764
Ester breakage of the compound will help you identify it.

thankyou so much ))

 

[Hamnah Zahoor]

t

thankyou so much ))

You are welcome.

 

[A*****]

Help me with this please

 

[MShaheerUddin]

HELP

 

[Metanoia]

View attachment 63771
HELP

Alkenes --> diols (adding 2 OH) groups

requires cold, dilute KMnO4

 

[sukasukinya]

can someone help me with this question?

 

[A*****]

View attachment 63773
can someone help me with this question?

Is it C?

 

[MShaheerUddin]

 

[Hamnah Zahoor]

^ Here I have solved this question before.

I had the same problem in this question when I solved this paper but now after repeated tries I was able to solve it correctly Alhamdulillah.
First find the value of the constant K as the angle of deflection is directly proportional to the charge mass ratio
PROTON:
Angle=+15 Charge= + mass= 1
15= k(+/1) thus K=+15

Option 1 :
Charge= +1-2= -1
mass= (atomic mass) 1+2=3
k=+15
Angle= (+15)*(-1/3)= -5..............option 1 correct

Option 2 :
Charge = +3-5 = -2
mass=3+3 =6
K=+15
Angle = (+15)*(-2/6) = -5..................option 2 is also correct

Option 3 :
Charge :4-1 = +3
mass=4+5 =9
K=+15
Angle = (+15)*(+3/9) = +5.......................Option 3 is incorrect.

Ans: B

 

[MShaheerUddin]

Thank you :O

 

[Hamnah Zahoor]

Thank you :O

I am glad it helped.

 

[MShaheerUddin]

 

[MShaheerUddin]

 

[A*****]

View attachment 63778

A?

 

[MShaheerUddin]

Yes

 

[SohaibButt]

Need help

 

[Kanekii]

Need helpView attachment 63782

Its B, since yellow ppt is formed by silver iodide.
and Ba because group 2 sulfates solubility decreases down the group so Ba is less soluble than Mg and will form a precipitate.