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Chemistry: Post your doubts here!

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If you find the ratio of salt to sulphite( simply by finding moles of salt and sulphite according to the info given) it comes out to be 2:1
& the equation shows 1 mole of sulphite looses 2 electron, therefore 2 mol of metallic salt gain those 2 electrons or 1 mol of metallic salt gains 1 mol of electron
therefore new O.N. of metal = +3-1=+2!

so if metallic salt gains those 2 electrons so why is +3 subtracted by -1 and not with -2.
 
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The answer to this is C...although I know that there will be no dipole moment in CO2 but does that also mean that it will not have permanent dipole-dipole interactions?
 

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Screen Shot 2018-06-03 at 1.49.00 PM.png
I really can't figure this out. How can the formula be like that? Isn't it going to be 2 Ca ? The answer is C btw. Helppp
 
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View attachment 63791
I really can't figure this out. How can the formula be like that? Isn't it going to be 2 Ca ? The answer is C btw. Helppp
It says salt formation so the ratio of acid to calcium would be 2:1 for example for Butanedioic acid seperate into two parts and react it with calicum and it will look like this :
CH2COO- + Ca2+ = (CH2COO)2 Ca
And do that for the rest and so its formula will become
C8H8O8Ca2
Divide by 2 and so the E.F becomes
C4H4O4Ca
 
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pretty stupid question but we are given data booklet in chemistry paper 1 right? we are allowed to use it right
 
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It says salt formation so the ratio of acid to calcium would be 2:1 for example for Butanedioic acid seperate into two parts and react it with calicum and it will look like this :
CH2COO- + Ca2+ = (CH2COO)2 Ca
And do that for the rest and so its formula will become
C8H8O8Ca2
Divide by 2 and so the E.F becomes
C4H4O4Ca
Thank youuuuu
 
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why is it C and not B?
As the reactants react they produce auto catalyst with the products so the rate increases but later after some time the the rate will decrease due to low substrate concentration.
 
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As the reactants react they produce auto catalyst with the products so the rate increases but later after some time the the rate will decrease due to low substrate concentration.
is shape of graph B for conc against time for auto-catalytic reaction?
 
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Guys check the page @threesciencesforalevel on insta...
You'll be surprised at what you will find. Unfortunately, I just got to see it now :"(
 
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Screenshot_20180603_225625.png


Plz someone guide me on how to balance such equations...will be really grateful
 
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upload_2018-6-4_1-35-0.png


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can anyone pls explain me how to solve these two questions
 

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