- Messages
- 2,951
- Reaction score
- 17,783
- Points
- 523
can u give me the link please? i'll try to... its a good revision
-
Prepare by Xtremepapers!
🚀 NEW from the xtremepape.rs team: AI exam prep — 150,000+ worked solutions, and it marks your handwritten working from a photo. Sign in with your forum account & try it free → prepare.xtremepape.rs
Chemistry: Post your doubts here!
- Thread starter XPFMember
- Start date
- Messages
- 532
- Reaction score
- 151
- Points
- 53
How does concentrated sulfuric acid behave when it reacts with sodium chloride?
A as an acid only
B as an acid and oxidising agent
C as an oxidising agent only
D as a reducing agent only
A as an acid only
B as an acid and oxidising agent
C as an oxidising agent only
D as a reducing agent only
An aqueous solution was prepared containing 1.0mol of AgNO3 and 1.0mol of FeSO4 in 1.00 dm3
of water. When equilibrium was established, there was 0.44mol of Ag+(aq) in the mixture.
Ag+(aq) + Fe2+(aq) --> Ag(s) + Fe3+(aq)
What is Kc?
A. 0.35 B. 0.62 C. 1.62 D. 2.89
I got C as my answer but the correct one is D, can anyone explain how to get D?
Edit: Oops I missed out the question! I just added it
of water. When equilibrium was established, there was 0.44mol of Ag+(aq) in the mixture.
Ag+(aq) + Fe2+(aq) --> Ag(s) + Fe3+(aq)
What is Kc?
A. 0.35 B. 0.62 C. 1.62 D. 2.89
I got C as my answer but the correct one is D, can anyone explain how to get D?
Edit: Oops I missed out the question! I just added it
answer is A. Here's a good link to explain why: http://www.chemguide.co.uk/inorganic/group7/halideions.html
Also check out my question if you can help me
- Messages
- 198
- Reaction score
- 47
- Points
- 28
wht is the Q
I don't understand? Do you mean what is the question? If you mean that, you just replied to it
EDIT: Ooops sorry!!! Here's the question:
What is Kc?
- Messages
- 466
- Reaction score
- 101
- Points
- 53
please some one help as soon as possiblecan u give me the link please? i'll try to... its a good revision
oct/nov 2010 second variant numer-7,18,31,34,36. soory for so much question but what can i do the paper semmed hard for me got these mistakes and unfortunately coudnt resolve any of my mistakes
thanks for helping all xpc members
http://www.xtremepapers.com/papers/... AS Level/Chemistry (9701)/9701_w10_qp_12.pdf
this was what i posted there.
thanks for helping.
- Messages
- 2,951
- Reaction score
- 17,783
- Points
- 523
its alrightplease some one help as soon as possible
oct/nov 2010 second variant numer-7,18,31,34,36. soory for so much question but what can i do the paper semmed hard for me got these mistakes and unfortunately coudnt resolve any of my mistakes
thanks for helping all xpc members
http://www.xtremepapers.com/papers/... AS Level/Chemistry (9701)/9701_w10_qp_12.pdf
this was what i posted there.
thanks for helping.
can u please give me a direct link to the paper itself cuz i cant find it atm... den i'll try 2 solve dem
I asked this question already, but just thought I post it again since we're on a new page.
An aqueous solution was prepared containing 1.0mol of AgNO3 and 1.0mol of FeSO4 in 1.00 dm3
of water. When equilibrium was established, there was 0.44mol of Ag+(aq) in the mixture.
Ag+(aq) + Fe2+(aq) --> Ag(s) + Fe3+(aq)
What is Kc?
A. 0.35 B. 0.62 C. 1.62 D. 2.89
I got C as my answer but the correct one is D, can anyone explain how to get D?
An aqueous solution was prepared containing 1.0mol of AgNO3 and 1.0mol of FeSO4 in 1.00 dm3
of water. When equilibrium was established, there was 0.44mol of Ag+(aq) in the mixture.
Ag+(aq) + Fe2+(aq) --> Ag(s) + Fe3+(aq)
What is Kc?
A. 0.35 B. 0.62 C. 1.62 D. 2.89
I got C as my answer but the correct one is D, can anyone explain how to get D?
- Messages
- 2,951
- Reaction score
- 17,783
- Points
- 523
even i am getting option C. Can you tell me which year paper is it ?
- Messages
- 198
- Reaction score
- 47
- Points
- 28
me neither trying frm long!!I'm not getting any of the options
wat method r u using please?
2. Total Flask Volume=5+10= 15dm3=15/1000 m3
Next work out the number of moles of helium and neon with pv=nRT
n=pv/RT
Since RT is constant throughout, let's make life easier by letting RT be an unknown, let's say A
For helium: n=[12000*(5/1000)]/A
For Neon: n=[6000*(10/1000)]/A
Total n=120/A
To find total P, use pv=nRT=nA
pV=nA
p=nA/V
p=[(120/A)*A]/(15/1000)
p=8000Pa=8kPa
- Messages
- 2,951
- Reaction score
- 17,783
- Points
- 523
its winter 2011 variant 13 question 12. No examiners report out yet unfortunately
http://www.xtremepapers.com/papers/... AS Level/Chemistry (9701)/9701_w11_qp_13.pdf
- Messages
- 347
- Reaction score
- 17
- Points
- 28
I answered your first question, here is the next one:
When you polymerise, you start with many monomers to make one or a few polymers, because you are combining monomers.
so if you start with one mole of monomers, you combine them and you end up with less monomers, therefore the answer could be from anything less than 1 mole to the minimum of 1 molecule, which the inverse of 6.02*10^23, option 3 of the question
- Messages
- 3,063
- Reaction score
- 1,831
- Points
- 173
10 cm3 of hydrocarbon is burned in 70cm3 of oxygen(excess) the funal gaseous mixture contains 30cm3 of ccarbon dioxide n 20 cm3 of unreacrted oxygen.whats the formula of hydrocarbon?
a) C2H5 b)C3H6 c)C3H8 d)C4H10
hows it c? these r supoosed 2 be easy questions bt cant get the answers
a) C2H5 b)C3H6 c)C3H8 d)C4H10
hows it c? these r supoosed 2 be easy questions bt cant get the answers
No point telling you my method, i got the wrong answer toome neither trying frm long!!