• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Chemistry: Post your doubts here!

Messages
347
Reaction score
17
Points
28
Remember this: Bond breaking is endothermic(positive) and Bond making is exothermic(negative)
Enthalpy changes:
P=+193 Br-Br bond broken
Q=-244 Cl-Cl made
R=-340 C-Cl made
S=+410 C-H broken
Answer C. RQPS
thamks. plz see if u can explain 21 of the same paper as well!
 
Messages
3,063
Reaction score
1,831
Points
173
10 cm3 of hydrocarbon is burned in 70cm3 of oxygen(excess) the funal gaseous mixture contains 30cm3 of ccarbon dioxide n 20 cm3 of unreacrted oxygen.whats the formula of hydrocarbon?
a) C2H5 b)C3H6 c)C3H8 d)C4H10
hows it c? these r supoosed 2 be easy questions bt cant get the answers:cry:

can any1 help em out here??
 
Messages
103
Reaction score
48
Points
38
thanks..could you please solve 21 of the same paper?
The Cl radical can bond to any CH3 or CH2 carbons by substituting a hydrogen. There are 5 such carbons here, however there are 3 CH3 groups bonded directly to the alpha central carbon. If the Cl radical bonds to any three of this, you get the same molecule. The 3 CH3 groups form only one type of molecule. There are another two carbons which Cl can bond to, which makes 3 Chloroalkanes in total.
Answer: C. 3 (I checked)
Sorry for the messy explanation, not very good at this, ask me to clarify if needed
EDIT: Fixed typo
 
Messages
51
Reaction score
22
Points
18
can any1 help em out here??
the general equation for combustion of hydro carbon is CxHy+x(y/4)O2----->XCO2+(y/2)H2O
in such question volume ratio is molar ratio .........1 mol of hydrcarbon produces 3 mol of CO2 thus the carbon atoms are three......... 10cm3of hydrocarbon:50cm3 oxygen(70-20)
thus it is 1:5 if we put 5 in the general equation we get..... x+(y/4)=5 futhur solve t it is y=8.....
thus CxHy=C3H8
 
Messages
3,063
Reaction score
1,831
Points
173
the general equation for combustion of hydro carbon is CxHy+x(y/4)O2----->XCO2+(y/2)H2O
in such question volume ratio is molar ratio .........1 mol of hydrcarbon produces 3 mol of CO2 thus the carbon atoms are three......... 10cm3of hydrocarbon:50cm3 oxygen(70-20)
thus it is 1:5 if we put 5 in the general equation we get..... x+(y/4)=5 futhur solve t it is y=8.....
thus CxHy=C3H8
umm thnx bt i didnt get the x+(y/4) thing??
 
Messages
103
Reaction score
48
Points
38
Can someone help?

Aqueous sodium chloride (brine) is electrolysed by using inert electrodes in a cell which is stirred
so that products of electrolysis react with each other. The cell is kept cold.
Which pair of substances is among the major products?
A hydrogen and chlorine
B hydrogen and sodium chlorate(I)
C hydrogen and sodium chlorate(V)
D sodium hydroxide and chlorine

http://www.xtremepapers.com/papers/... AS Level/Chemistry (9701)/9701_w11_qp_13.pdf
Q17
I chose D but the answer is B. I know that sodium chlorate and hydrogen is made, therefore B is right but isnt D also right because NaOH and Cl2 is also made?
 
Messages
51
Reaction score
22
Points
18
Can someone help?

Aqueous sodium chloride (brine) is electrolysed by using inert electrodes in a cell which is stirred
so that products of electrolysis react with each other. The cell is kept cold.
Which pair of substances is among the major products?
A hydrogen and chlorine
B hydrogen and sodium chlorate(I)
C hydrogen and sodium chlorate(V)
D sodium hydroxide and chlorine

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w11_qp_13.pdf
Q17
I chose D but the answer is B. I know that sodium chlorate and hydrogen is made, therefore B is right but isnt D also right because NaOH and Cl2 is also made?

The products of the electrolysis are Cl2 and H2 and NaOH...but when the products are mixed there is a reaction between NaOH and Cl2.....since the conditions are cold the products are NaClO+H2+NaCl+H2O
 
Messages
532
Reaction score
151
Points
53
An aqueous solution was prepared containing 1.0mol of AgNO3 and 1.0mol of FeSO4 in 1.00 dm3
of water. When equilibrium was established, there was 0.44mol of Ag+(aq) in the mixture.
Ag+(aq) + Fe2+(aq) --> Ag(s) + Fe3+(aq)

What is Kc?

A. 0.35 B. 0.62 C. 1.62 D. 2.89

I got C as my answer but the correct one is D, can anyone explain how to get D?

Edit: Oops I missed out the question! I just added it
dont add Ag(s) in calculating kc value as kc is used only for aques medium...
 
Top